When a conductor carrying an electric current \$I\$ is placed in a magnetic field \$\\mathbf{B}\$, it experiences a magnetic force. The force is given by the cross‑product:
\$\\mathbf{F}=I\\,\\mathbf{L}\\times\\mathbf{B}\$
Here \$\\mathbf{L}\$ is the vector that points along the length of the conductor, its magnitude being the length \$L\$. The direction of \$\\mathbf{F}\$ follows the right‑hand rule: point your fingers in the direction of \$\\mathbf{L}\$, curl them toward \$\\mathbf{B}\$, and your thumb points in the direction of the force.
In devices such as electric motors, the magnetic force turns the rotor. In particle detectors, it bends the path of charged particles, allowing us to measure their properties.
Charged particles moving through perpendicular electric \$\\mathbf{E}\$ and magnetic \$\\mathbf{B}\$ fields can be filtered by their velocity. The key idea is to balance the electric and magnetic forces so that only particles with a specific speed pass straight through.
The electric force is \$\\mathbf{F}E=q\\,\\mathbf{E}\$ and the magnetic force is \$\\mathbf{F}B=q\\,\\mathbf{v}\\times\\mathbf{B}\$. For a particle to travel undeflected, these forces must cancel:
\$q\\,\\mathbf{E}=q\\,\\mathbf{v}\\times\\mathbf{B}\$
Assuming \$\\mathbf{E}\$ and \$\\mathbf{B}\$ are perpendicular and the velocity \$\\mathbf{v}\$ is along the conductor, we get the simple relation:
\$v=\\frac{E}{B}\$
Only particles with speed \$v\$ will go straight; others will be deflected.
| Velocity \$v\$ | Electric Force \$F_E\$ | Magnetic Force \$F_B\$ | Resulting Path |
|---|---|---|---|
| \$v = E/B\$ | \$qE\$ | \$qE\$ | Straight line 🚶♂️ |
| \$v > E/B\$ | \$qE\$ | \$>qE\$ | Deflected left 🔄 |
| \$v < E/B\$ | \$qE\$ | \$ | Deflected right 🔄 |