Published by Patrick Mutisya · 8 days ago
Understand that radioactive decay is both spontaneous and random.
Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. The nucleus transforms into a different nucleus (or the same element in an excited state) without any external influence.
The decay occurs without any external trigger. Even in a perfectly isolated environment, an unstable nucleus will eventually decay.
While the overall behaviour of a large collection of nuclei can be described by simple laws, the exact moment at which any single nucleus decays is unpredictable.
The number of undecayed nuclei \$N\$ after a time \$t\$ is given by the exponential decay law:
\$N(t) = N_0 e^{-\\lambda t}\$
where:
The half‑life \$T_{1/2}\$ is the time required for half of the original nuclei to decay. It is related to the decay constant by:
\$T_{1/2} = \\frac{\\ln 2}{\\lambda}\$
| Decay Type | Particle Emitted | Change in Atomic Number (Z) | Change in Mass Number (A) | Typical Energy (MeV) |
|---|---|---|---|---|
| Alpha (α) decay | He nucleus (\$^4_2\\text{He}\$) | -2 | -4 | 4–9 |
| Beta‑minus (β⁻) decay | Electron (\$e^-\$) + antineutrino (\$\\bar{\\nu}_e\$) | +1 | 0 | 0.1–3 |
| Beta‑plus (β⁺) decay | Positron (\$e^+\$) + neutrino (\$\\nu_e\$) | -1 | 0 | 0.5–3 |
| Gamma (γ) emission | Photon (γ ray) | 0 | 0 | 0.1–10 |
Consider a sample containing \$1.0\\times10^{6}\$ atoms of a radionuclide with a half‑life of 30 minutes. After 90 minutes (three half‑lives), the number of remaining atoms is:
\$\$N = N0 \\left(\\frac{1}{2}\\right)^{\\frac{t}{T{1/2}}}
= 1.0\\times10^{6} \\left(\\frac{1}{2}\\right)^{3}
= 1.25\\times10^{5}\$\$
This calculation shows the predictable statistical behaviour of a large ensemble, even though the exact decay time of any individual atom remains unknown.