Published by Patrick Mutisya · 8 days ago
Describe an experiment to determine the resistance of a component using a voltmeter and an ammeter, and perform the required calculations.
The relationship between voltage (\$V\$), current (\$I\$) and resistance (\$R\$) for an ohmic conductor is given by Ohm’s law:
\$\$
V = I R
\$\$
Re‑arranging gives the expression for resistance:
\$\$
R = \frac{V}{I}
\$\$
By measuring \$V\$ across the component and the current \$I\$ flowing through it, the resistance can be calculated.
| Supply \cdot oltage \$V_{\text{set}}\$ (V) | Measured \cdot oltage \$V\$ (V) | Measured Current \$I\$ (A) | Calculated Resistance \$R = V/I\$ (Ω) |
|---|---|---|---|
| 2 | |||
| 4 | |||
| 6 | |||
| 8 | |||
| 10 |
For each row, calculate the resistance using:
\$\$
R = \frac{V}{I}
\$\$
To obtain a single best estimate of the resistance, take the average of the individual \$R\$ values:
\$\$
\overline{R} = \frac{\sum{k=1}^{n} Rk}{n}
\$\$
where \$n\$ is the number of measurements.
Assume the following recorded values for the 4 V setting:
\$\$
V = 3.96\ \text{V}, \qquad I = 0.020\ \text{A}
\$\$
Then
\$\$
R = \frac{3.96\ \text{V}}{0.020\ \text{A}} = 198\ \Omega
\$\$
If the five calculated resistances are 198 Ω, 200 Ω, 202 Ω, 199 Ω and 201 Ω, the average resistance is
\$\$
\overline{R} = \frac{198 + 200 + 202 + 199 + 201}{5} = 200\ \Omega
\$\$
By measuring voltage across and current through a component, the resistance can be calculated using Ohm’s law. Repeating the measurement at several voltages and averaging reduces random errors, giving a reliable value for the unknown resistance.