Published by Patrick Mutisya · 8 days ago
State that, for a parallel circuit, the current supplied by the source is larger than the current flowing in any individual branch.
\$I{\text{total}} = I1 + I2 + I3 + \dots\$
\$I{\text{total}} > In \quad \text{for all } n.\$
\$\frac{1}{R{\text{eq}}}= \frac{1}{R1}+ \frac{1}{R2}+ \frac{1}{R3}+ \dots\$
Consider a parallel circuit with two branches, each containing a resistor \$R1\$ and \$R2\$ respectively, connected to a battery of emf \$V\$.
\$I1 = \frac{V}{R1}, \qquad I2 = \frac{V}{R2}.\$
\$I{\text{total}} = I1 + I2 = \frac{V}{R1} + \frac{V}{R_2}.\$
| Feature | Series Circuit | Parallel Circuit |
|---|---|---|
| Current through each component | Same throughout the circuit (\$I{\text{total}} = I1 = I_2 = \dots\$) | Different in each branch; \$I{\text{total}} = I1 + I_2 + \dots\$ |
| Voltage across each component | Divides according to resistance (\$V{\text{total}} = V1 + V_2 + \dots\$) | Same across each branch (all experience the source voltage \$V\$) |
| Equivalent resistance | \$R{\text{eq}} = R1 + R_2 + \dots\$ (greater than any individual \$R\$) | \$\displaystyle\frac{1}{R{\text{eq}}}= \frac{1}{R1}+ \frac{1}{R_2}+ \dots\$ (less than any individual \$R\$) |
| Source current compared to branch currents | Source current equals the current in each component. | Source current is larger than the current in any single branch. |
Calculate the total current supplied by a 12 V battery connected to two parallel resistors, \$R1 = 6\ \Omega\$ and \$R2 = 12\ \Omega\$.
\$\$I_1 = \frac{12\ \text{V}}{6\ \Omega}=2\ \text{A},\qquad
I_2 = \frac{12\ \text{V}}{12\ \Omega}=1\ \text{A}.\$\$
\$I{\text{total}} = I1 + I_2 = 2\ \text{A} + 1\ \text{A}=3\ \text{A}.\$
Three resistors \$R1 = 4\ \Omega\$, \$R2 = 6\ \Omega\$, and \$R_3 = 12\ \Omega\$ are connected in parallel across a 9 V source. Calculate the current supplied by the source and state whether it is larger than the current in each branch.