Draw and interpret circuit diagrams containing cells, batteries, power supplies, generators, potential dividers, switches, resistors (fixed and variable), heaters, thermistors (NTC only), light-dependent resistors (LDRs), lamps, motors, bells, ammete

4.3.1 Circuit Diagrams and Circuit Components

Learning objectives

  • Draw accurate circuit diagrams that include every core IGCSE 0625 component and the required supplementary symbols (diodes, LEDs, fuses, relays, safety symbols).
  • Interpret a given diagram – identify each symbol, its polarity or switching state, and predict the overall electrical behaviour (current, voltage, power).
  • Apply the fundamental series‑parallel laws, Kirchhoff’s voltage and current laws, and the power‑energy relationships when analysing circuits.

Fundamental circuit laws (quick reference)

  • Series circuit: same current flows through each element; total resistance \(R{\text{tot}} = R1+R_2+\dots\).
  • Parallel circuit: same potential difference across each branch; total conductance \(G{\text{tot}} = G1+G2+\dots\) where \(G = 1/R\). Hence \(\displaystyle \frac{1}{R{\text{tot}}}= \frac{1}{R1}+ \frac{1}{R2}+ \dots\).
  • Kirchhoff’s Voltage Law (KVL): the algebraic sum of all potential differences round any closed loop is zero.
  • Kirchhoff’s Current Law (KCL): the algebraic sum of currents entering a junction equals the sum leaving it.
  • Power and energy: \(P = VI = I^{2}R = \dfrac{V^{2}}{R}\); \(E = Pt\) (where \(t\) is time in seconds).

Standard symbols (Cambridge‑approved)

ComponentSymbolPolarity / Connection notesGoverning equation / quantitative behaviourTypical values / remarks
Cell (single)cellLong line = positive terminal, short line = negative terminal.Provides a constant emf \(E\). No load current‑voltage equation is required for the symbol itself.Typical emf: 1.5 V (dry cell), 9 V (rectangular). Internal resistance ≈ 0.1 Ω.
Battery (multiple cells in series)batterySeries‑connected cells; terminals marked “+” and “–”.Emf \(E = nE_{\text{cell}}\) where \(n\) is the number of cells.Common values: 6 V (four 1.5 V cells), 12 V (eight cells). Internal resistance a few Ω for large batteries.
Power supply / Generator (DC or AC)generatorPositive and negative terminals shown; AC symbols may include a tilde (~) inside the circle.DC: \(V = E\) (adjustable). AC: \(V(t)=V_{\text{peak}}\sin\omega t\).Adjustable lab supplies: 0–30 V, up to 5 A. Internal resistance < 0.1 Ω.
Potential divider (two resistors in series with a tap)potential dividerTap taken from the junction of the two resistors.\(V{\text{tap}} = V{\text{total}}\dfrac{R2}{R1+R2}\). Current \(I = \dfrac{V{\text{total}}}{R1+R2}\).Typical \(R\) values: 1 kΩ – 1 MΩ. Used for reference voltages (e.g., 5 V from 12 V).
Switch (single‑pole, single‑throw)open switchOpen symbol shown; a closed switch is drawn with a short diagonal line joining the contacts.When closed, the switch contributes negligible resistance; when open, it breaks the circuit (infinite resistance).Mechanical switches: 0.1 Ω closed, > 10 MΩ open.
Fixed resistorresistorConnected in any orientation; colour‑code not shown in diagram.Ohm’s law: \(V = IR\).Common range: 10 Ω – 10 MΩ. Power rating: 0.25 W, 0.5 W, 1 W.
Variable resistor (potentiometer)potentiometerWiper (the triangle) taps the resistor at a variable point.\(R{\text{eq}} = R{\text{min}} + \alpha R_{\text{total}}\) where \(\alpha\) is the wiper position (0 – 1).Typical total resistance: 1 kΩ – 10 kΩ. Power rating usually 0.25 W.
Heater (resistive element)heaterTerminals are not polarised.Power dissipated \(P = I^{2}R = VI\). Temperature rise ∝ \(P\).Typical resistance: 5 Ω – 50 Ω; power rating 10 W – 1500 W.
Thermistor (NTC)NTC thermistorMarked “T” to remind that resistance varies with temperature.\(R = R_{0}\,e^{-\beta T}\) (approx.) or use the datasheet β‑value. \( \displaystyle \frac{dR}{dT}<0\).Typical: \(R_{0}=10 kΩ\) at 25 °C, β ≈ 0.04 K⁻¹.
Light‑dependent resistor (LDR)LDRCircle with a vertical line denotes a light‑sensitive element.\(R = R{\text{dark}} \left(\frac{L{0}}{L}\right)^{\gamma}\) (qualitative). Resistance falls as illumination \(L\) increases.Typical: 1 kΩ (bright) – 1 MΩ (dark). γ ≈ 0.5‑0.8.
Lamp (incandescent)lampNon‑polarised; filament is a resistive element whose resistance rises with temperature.Power \(P = VI\). Filament resistance roughly doubles when hot.Typical rating: 5 W – 100 W (≈ 10 V – 240 V). Cold resistance ≈ 1/10 of hot resistance.
Motor (DC)motorPolarity matters – reversing the connections reverses rotation.Effective voltage \(V{\text{net}} = V{\text{applied}} - E{\text{b}}\) where back‑EMF \(E{\text{b}} = k\omega\). Current \(I = \dfrac{V{\text{net}}}{R{\text{arm}}}\).Small hobby motors: 3 V – 12 V, armature resistance 5 Ω – 20 Ω.
Bell (electromagnet)bellCoil is polarised; the hammer moves when current flows.Current creates a magnetic field; the mechanical work is small compared with electrical power input.Typical coil resistance 10 Ω – 50 Ω, operates from 6 V – 12 V.
AmmeterammeterConnected in series; internal resistance ≪ circuit resistance.Measures current \(I\). No equation needed beyond series connection.Range: 0‑10 A (typical), 0‑0.1 A for sensitive meters.
VoltmetervoltmeterConnected in parallel; internal resistance ≫ circuit resistance.Measures potential difference \(V\) across its terminals.Range: 0‑500 V (typical), 0‑10 V for fine measurements.
Magnetising coil (inductor)inductorPolarity not indicated; symbol may be drawn with a dot for the start of the coil.Induced emf \(V_L = -L\frac{dI}{dt}\). Energy stored \(U = \tfrac12 LI^{2}\).Typical inductance: 10 mH – 10 H (lab coils).
Transformer (ideal)transformerPrimary and secondary windings are shown; dots indicate the same polarity ends.\(\displaystyle \frac{Vs}{Vp} = \frac{Ns}{Np}\), \(\displaystyle \frac{Is}{Ip} = \frac{Np}{Ns}\) (ideal, no losses).Step‑up or step‑down ratios from 1:1 to 10:1 are common in exam questions.
FusefusePlaced in series; melts if current exceeds rating.Current rating \(If\); when \(I > If\) for a short time the fuse opens (infinite resistance).Typical: 0.5 A, 1 A, 3 A, 5 A.
Relay (electromagnetic switch)relayCoil (left) controls a set of contacts (right). Coil is polarised; contacts may be normally open (NO) or normally closed (NC).When coil current flows, magnetic force moves contacts, changing the circuit path.Coil voltage: 5 V‑12 V; contact rating up to several amperes.
Diode (supplementary)diodeTriangle points towards the line – arrow indicates forward direction (conventional current flows from anode to cathode).Ideal I‑V: \(I = 0\) for \(V < 0\); \(I\) unrestricted for \(V \ge 0\). Real diode: \(I = IS\big(e^{V/nVT}-1\big)\).Silicon diode forward voltage ≈ 0.7 V; reverse breakdown ≈ 50 V – 1000 V.
LED (Light‑Emitting Diode) – supplementaryLEDSame polarity as a diode; two small arrows indicate light emission.Forward voltage 1.8 V – 3.3 V depending on colour. I‑V similar to diode, but with a characteristic knee.Typical current 10 mA – 20 mA; power rating ≈ 20 mW.
Earth (ground) symbol – safetyearthUsed to show a protective earth connection; always drawn at the low‑potential side of a circuit.No electrical equation; indicates safety compliance.Mandatory in all exam diagrams that involve metal enclosures or appliances.

How to interpret a circuit diagram (step‑by‑step)

  1. Identify sources and their polarity. Mark the + and – terminals of cells, batteries or power supplies.
  2. Locate series and parallel groups. Use KVL for each closed loop and KCL at each junction.
  3. Replace complex symbols with their equations. For example, replace a potential divider with two resistors and apply the divider formula.
  4. Insert measuring instruments correctly. Ammeter in series, voltmeter in parallel; remember their internal resistances.
  5. Calculate currents, voltages and power. Start with the simplest loop, solve for unknowns, then work outward.
  6. Check safety symbols. Ensure fuses, earth connections and relays are placed as shown – they do not affect the ideal calculations but are essential for real‑world design.

Example: Simple lighting circuit

Diagram (text description): A 6 V battery (cell + cell) → switch (open) → series resistor 220 Ω → lamp (30 W) → back to the battery negative terminal. A voltmeter is connected across the lamp.

  • When the switch is closed, total series resistance \(R{\text{tot}} = 220 Ω + R{\text{lamp}}\).
  • Assuming the lamp operates at its rated power, its hot resistance \(R_{\text{lamp}} = \dfrac{V^{2}}{P} = \dfrac{6^{2}}{30} = 1.2 Ω\).
  • Current \(I = \dfrac{6 \text{V}}{220 Ω + 1.2 Ω} \approx 0.027 \text{A}\).
  • Voltage across the lamp \(V{\text{lamp}} = I \times R{\text{lamp}} \approx 0.032 \text{V}\) – the lamp will be very dim because the series resistor is far too large.
  • The voltmeter reads ≈ 0.03 V, confirming the calculation.

This example illustrates how the symbol table, series‑parallel laws and the power equation combine to predict circuit behaviour.

Key points to remember for the exam

  • All symbols must be drawn exactly as in the Cambridge standard – any deviation may lose marks.
  • Always show polarity for cells, batteries and diodes/LEDs.
  • State the governing equation for each component when you are asked to “explain” the behaviour.
  • Use KVL and KCL systematically; they are worth a separate mark in many questions.
  • Include safety symbols (fuse, earth, relay contacts) when the question context involves appliances or protective devices.
  • When a component is “non‑linear” (lamp, thermistor, LDR, diode) indicate the qualitative trend (e.g., resistance decreases with temperature or light) and, if required, write the appropriate approximate formula.