Published by Patrick Mutisya · 14 days ago
Define resultant force as the change in momentum per unit time and use the equation
\$F = \frac{\Delta p}{\Delta t}\$
to solve problems.
\$\mathbf{F}_{\text{resultant}} = \frac{\Delta \mathbf{p}}{\Delta t}\$
Starting from the definition of momentum:
\$p = mv\$
For a constant mass, the change in momentum over a time interval \$\Delta t\$ is:
\$\Delta p = m\Delta v\$
Dividing both sides by \$\Delta t\$ gives the average resultant force during that interval:
\$F_{\text{avg}} = \frac{\Delta p}{\Delta t} = m\frac{\Delta v}{\Delta t} = ma\$
In the limit as \$\Delta t \to 0\$, the average force becomes the instantaneous force:
\$\mathbf{F} = \frac{d\mathbf{p}}{dt}\$
| Quantity | Symbol | SI Unit | Unit Symbol |
|---|---|---|---|
| Momentum | \$p\$ | kilogram metre per second | kg·m·s⁻¹ |
| Force | \$F\$ | newton | N |
| Time | \$t\$ | second | s |
Problem: A 0.15 kg ball is struck and its velocity changes from 2.0 m s⁻¹ to 8.0 m s⁻¹ in 0.05 s. Find the average resultant force exerted on the ball.
\$\Delta p = pf - pi = 1.20 - 0.30 = 0.90\ \text{kg·m·s}^{-1}\$
\$F_{\text{avg}} = \frac{\Delta p}{\Delta t} = \frac{0.90}{0.05} = 18\ \text{N}\$
The resultant (net) force acting on an object is defined as the rate at which its momentum changes:
\$\mathbf{F}_{\text{resultant}} = \frac{\Delta \mathbf{p}}{\Delta t}\$
This relationship is fundamental for solving problems involving collisions, rockets, and any situation where mass may change or forces act over short time intervals.