Published by Patrick Mutisya · 14 days ago
Understand how a Hall probe can be used to measure the magnetic flux density \$B\$ in a region where a conductor carrying current \$I\$ experiences a magnetic force.
The magnetic force on a straight conductor of length \$L\$ carrying a current \$I\$ in a uniform magnetic field \$\mathbf{B}\$ is given by the Lorentz force law:
\$\mathbf{F}=I\,\mathbf{L}\times\mathbf{B}\$
For a conductor oriented perpendicular to the field, the magnitude simplifies to:
\$F = I L B \sin\theta\$
where \$\theta\$ is the angle between \$\mathbf{L}\$ and \$\mathbf{B}\$. When \$\theta = 90^{\circ}\$, \$\sin\theta = 1\$ and \$F = I L B\$.
When a current \$I{\text{H}}\$ flows through a thin semiconductor plate placed in a magnetic field \$B\$, charge carriers experience a magnetic force that drives them to one side of the plate, creating a transverse voltage \$V{\text{H}}\$ – the Hall voltage.
The Hall voltage is related to the magnetic flux density by:
\$V{\text{H}} = \frac{I{\text{H}} B}{n q t}\$
where:
Rearranging gives the magnetic flux density:
\$B = \frac{V{\text{H}} n q t}{I{\text{H}}}\$
A Hall probe incorporates a calibrated Hall sensor and electronics that output \$B\$ directly, but the underlying principle follows the equation above. The steps are:
The following method links the measured \$B\$ to the magnetic force on a conductor.
Given:
| Quantity | Symbol | Value | Unit |
|---|---|---|---|
| Current through the wire | \$I\$ | 2.5 | A |
| Length of wire in field | \$L\$ | 0.150 | m |
| Magnetic flux density (Hall probe reading) | \$B\$ | 0.035 | T |
Force:
\$F = I L B = (2.5\ \text{A})(0.150\ \text{m})(0.035\ \text{T}) = 0.0131\ \text{N}\$
By measuring the magnetic flux density \$B\$ with a Hall probe, the magnetic force on a current‑carrying conductor can be quantified using \$F = I L B\$. The Hall effect provides a direct, reliable method for determining \$B\$, linking the electrical measurement (Hall voltage) to the mechanical effect (force).