Cambridge A-Level Physics 9702 – Energy and Momentum of a Photon
Energy and Momentum of a Photon
Learning Objective
Understand that photoelectrons may be emitted from a metal surface when it is illuminated by electromagnetic radiation.
1. Photons – Quantised Packets of Light
A photon is a quantum of electromagnetic radiation. Its energy \$E\$ and momentum \$p\$ are related to its frequency \$\nu\$ (or wavelength \$\lambda\$) by:
\$\$
E = h\nu = \frac{hc}{\lambda},\qquad p = \frac{E}{c} = \frac{h}{\lambda}
Controls number of photons per unit time → controls number of emitted electrons, not \$K_{\text{max}}\$
4. Momentum Transfer
When a photon ejects an electron, conservation of momentum must be considered. The photon’s momentum \$p = h/\lambda\$ is transferred to the electron and the metal lattice. In most A‑Level treatments, the recoil of the metal is negligible, but the concept reinforces the particle nature of light.
5. Example Calculation
Determine the maximum kinetic energy of electrons emitted from a sodium surface (\$\phi = 2.28\ \text{eV}\$) when illuminated with light of wavelength \$400\ \text{nm}\$.
Convert work function to joules: \$\phi = 2.28\ \text{eV} \times 1.602\times10^{-19}\ \text{J/eV} = 3.65\times10^{-19}\ \text{J}\$.
Maximum kinetic energy: \$K_{\text{max}} = E - \phi = 4.97\times10^{-19} - 3.65\times10^{-19} = 1.32\times10^{-19}\ \text{J}\$.
Convert back to electron‑volts: \$K_{\text{max}} = \dfrac{1.32\times10^{-19}}{1.602\times10^{-19}}\ \text{eV} \approx 0.82\ \text{eV}\$.
6. Experimental Setup (Suggested Diagram)
Suggested diagram: Schematic of a photoelectric experiment showing a light source, metal photocathode, anode, and variable stopping potential \$V_s\$.
7. Summary
Photons carry quantised energy \$E = h\nu\$ and momentum \$p = h/\lambda\$.
The photoelectric effect demonstrates the particle nature of light.
Emission occurs only when \$h\nu > \phi\$; the excess energy becomes kinetic energy of the electron.
The stopping potential provides a direct measurement of \$K_{\text{max}}\$ and allows determination of \$\phi\$.
Intensity affects the number of emitted electrons, not their kinetic energy.
8. Quick Revision Questions
What is the threshold frequency for a metal with work function \$4.5\ \text{eV}\$?
If light of wavelength \$250\ \text{nm}\$ shines on a metal with \$\phi = 3.0\ \text{eV}\$, calculate the stopping potential required to just stop the most energetic electrons.
Explain why increasing the intensity of light of frequency below the threshold does not cause electron emission.