Published by Patrick Mutisya · 14 days ago
Students should be able to state that electromotive force (e.m.f.) is measured in volts (V) and understand how this unit relates to other electrical quantities.
When a circuit is open (no current), the measured voltage across the terminals of a source equals its e.m.f. Once the circuit is closed, the internal resistance of the source causes a drop, so the terminal p.d. is slightly less than the e.m.f.
The SI unit of e.m.f. is the volt (V). By definition:
\$\$
1\ \text{V} = 1\ \frac{\text{joule}}{\text{coulomb}} = 1\ \frac{\text{J}}{\text{C}}
\$\$
Thus, a source with an e.m.f. of 1 V supplies 1 J of energy to each coulomb of charge that passes through it.
| Aspect | Electromotive Force (e.m.f.) | Potential Difference (p.d.) |
|---|---|---|
| When measured | Open‑circuit (no current) | Closed circuit (current flowing) |
| Cause | Energy supplied by source | Energy lost or gained as charge moves through components |
| Effect of internal resistance | Not affected (ideal condition) | Reduced by \$I r{\text{int}}\$ where \$I\$ is current and \$r{\text{int}}\$ is internal resistance |
| Symbol | \$\mathcal{E}\$ | \$V\$ |
| Unit | Volt (V) | Volt (V) |
To measure the e.m.f. of a source, use a voltmeter connected across the terminals while the circuit is open. The reading directly gives the e.m.f. in volts.
Electromotive force (e.m.f.) is the maximum potential difference a source can provide and is measured in volts (V). The relationship \$1\ \text{V}=1\ \text{J/C}\$ links the unit to fundamental energy and charge concepts. Understanding the distinction between e.m.f. and the potential difference across a component is essential for analysing real circuits.