Published by Patrick Mutisya · 14 days ago
By the end of this lesson you should be able to represent any vector as two perpendicular components.
Consider a vector \$\vec{A}\$ lying in the \$xy\$‑plane. It can be expressed as the sum of two perpendicular components along the \$x\$‑ and \$y\$‑axes:
\$\vec{A}=Ax\hat{i}+Ay\hat{j}\$
where:
If the magnitude \$A\$ and the angle \$\theta\$ (measured from the positive \$x\$‑axis) are known, the components are obtained using trigonometry:
\$A_x = A\cos\theta\$
\$A_y = A\sin\theta\$
The reverse relations give the magnitude and direction from the components:
\$A = \sqrt{Ax^{2}+Ay^{2}}\$
\$\theta = \tan^{-1}\!\left(\frac{Ay}{Ax}\right)\$
Given a force \$\vec{F}\$ of magnitude \$50\ \text{N}\$ acting \$30^{\circ}\$ above the positive \$x\$‑axis, find its components.
| Vector Quantity | Symbol | Typical Units | Typical Components |
|---|---|---|---|
| Displacement | \$\vec{s}\$ | metre (m) | \$sx\$, \$sy\$ |
| Velocity | \$\vec{v}\$ | metre per second (m s⁻¹) | \$vx\$, \$vy\$ |
| Acceleration | \$\vec{a}\$ | metre per second squared (m s⁻²) | \$ax\$, \$ay\$ |
| Force | \$\vec{F}\$ | newton (N) | \$Fx\$, \$Fy\$ |
Any vector in a plane can be uniquely described by two perpendicular components. This representation simplifies vector addition, subtraction, and the application of Newton’s laws in two dimensions.