x(t)=A\sin(2\pi ft)
where x = displacement, A = amplitude, f = frequency (Hz).
| Concept | Definition / Formula | Relevance to sound |
|---|---|---|
| Amplitude (A) | Maximum displacement of the source. | Controls loudness – larger A → louder. Quantitatively, intensity I ∝ A². |
| Frequency (f) | Number of vibrations per second (Hz). | Determines pitch – higher f → higher pitch. |
| Period (T) | T = 1/f | Time for one complete vibration. |
| Wavelength (λ) | λ = v / f | Distance between successive compressions (or rarefactions). |
| Speed of sound (v) |
In general | Sets the relationship between f and λ; varies with medium, temperature and density. |
| Audible frequency range | ≈ 20 Hz – 20 kHz for a healthy young adult. | All frequencies given in the tables fall within this range. |
| Ultrasound | Frequencies > 20 kHz. | Used in medical imaging, non‑destructive testing and sonar. |
| Source | Vibration mechanism | Typical frequency range (Hz) |
|---|---|---|
| String instrument (e.g., guitar) | Stretched string vibrates between two fixed ends; tension, length and linear mass density determine the frequency. | 80 – 1 200 |
| Wind instrument (e.g., flute) | Column of air vibrates; effective length set by finger holes or slides. | 200 – 2 000 |
| Membrane (e.g., drum) | Stretched membrane vibrates when struck; tension and diameter are key. | 50 – 500 |
| Vocal cords | Pairs of folds in the larynx vibrate as air passes through. | 85 – 1 100 (male), 165 – 2 200 (female) |
| Speaker diaphragm | Cone or dome vibrates due to alternating current in a coil. | 20 – 20 000 |
| Ultrasound transducer | Piezoelectric crystal vibrates at > 20 kHz. | 20 000 – 10 000 000 |
For a string of length L, tension T and linear mass density μ, the fundamental (first harmonic) frequency is
f₁ = \frac{1}{2L}\sqrt{\frac{T}{\mu}}
Given L = 0.65 m, T = 80 N, μ = 0.002 kg m⁻¹:
f₁ = \frac{1}{2(0.65)}\sqrt{\frac{80}{0.002}} ≈ 138 Hz
Interpretation: the string will produce a pitch of about 138 Hz – a low‑to‑mid musical note.
Using λ = v / f with v ≈ 340 m s⁻¹:
λ = 340 / 500 = 0.68 m
The distance between successive compressions is 0.68 m.
Place a flat wall a measured distance d from a loudspeaker. Emit a short pulse and record the time between the emitted pulse and the reflected pulse (the echo) using a stopwatch or a digital timer.
Speed of sound: v = 2d / Δt (the factor 2 accounts for the round‑trip).
Example: d = 5 m, measured echo time Δt = 0.029 s → v = 2×5 / 0.029 ≈ 345 m s⁻¹.
v = √(elastic modulus / density). Higher elastic modulus and lower density give a higher speed.v = √(E/ρ) for solids, v is large. For liquids v = √(B/ρ) with a smaller bulk modulus, and for gases both B and ρ are much smaller, giving the lowest speed.Sound is generated when a source vibrates, producing longitudinal pressure waves that travel through a medium. The pitch of the sound is set by the vibration frequency, which depends on tension, length, mass, and the elastic properties of the source and the medium. Loudness is controlled by the amplitude of vibration (intensity ∝ A²). The speed of sound varies with the medium because it depends on the ratio of its elastic modulus to its density, leading to the order solid > liquid > gas. Echoes arise from reflection, and ultrasound (> 20 kHz) finds important uses in medicine, industry and sonar.
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