Published by Patrick Mutisya · 14 days ago
Know that thermal radiation is infrared radiation and that all objects emit this radiation.
Thermal radiation is the electromagnetic energy released by a body as a result of its temperature. The term “thermal” links the radiation to the internal kinetic energy of the particles in the material.
Infrared (IR) radiation has wavelengths from about \$700\ \text{nm}\$ to \$1\ \text{mm}\$. It lies between visible light and microwaves in the electromagnetic spectrum.
According to the law of black‑body radiation, any object with temperature \$T > 0\ \text{K}\$ emits a continuous spectrum of radiation. The intensity \$I(\lambda,T)\$ at wavelength \$\lambda\$ is given by Planck’s law:
\$\$
I(\lambda,T)=\frac{2hc^{2}}{\lambda^{5}}\frac{1}{\exp\!\left(\frac{hc}{\lambda k_{\mathrm{B}}T}\right)-1}
\$\$
where \$h\$ is Planck’s constant, \$c\$ is the speed of light, and \$k_{\mathrm{B}}\$ is Boltzmann’s constant.
The wavelength \$\lambda_{\text{max}}\$ at which the emission is strongest is inversely proportional to the absolute temperature:
\$\$
\lambda_{\text{max}} = \frac{b}{T}
\$\$
with \$b \approx 2.898\times10^{-3}\ \text{m·K}\$. For typical room temperature (\$T \approx 300\ \text{K}\$), \$\lambda_{\text{max}} \approx 9.7\ \mu\text{m}\$, which lies in the infrared region.
| Object | Temperature (K) | Peak Wavelength \$\lambda_{\text{max}}\$ (µm) | Dominant Radiation |
|---|---|---|---|
| Human body | 310 | 9.3 | Infrared |
| Room temperature air | 293 | 9.9 | Infrared |
| Warm cup of tea | 350 | 8.3 | Infrared |
| Sun’s surface | 5800 | 0.5 | Visible (peak) + Infrared |
All objects with a temperature above absolute zero emit electromagnetic radiation. At the temperatures encountered in daily life, the peak of this emission lies in the infrared part of the spectrum, which is why we refer to it as thermal radiation. Understanding this concept is essential for topics such as heat transfer, remote sensing, and everyday technologies that rely on infrared.