explain that during oxidative phosphorylation: hydrogen atoms split into protons and energetic electrons, energetic electrons release energy as they pass through the electron transport chain (details of carriers are not expected), the released energy
Oxidative Phosphorylation (Stage 5 of Aerobic Respiration)
Cambridge syllabus links
AO1 – recall the location, reactants and products of oxidative phosphorylation.
AO2 – describe how the energy released by electrons is used to make ATP.
AO3 – evaluate experimental evidence (e.g., uncouplers, inhibitors) that supports the chemiosmotic hypothesis.
1. Where does it fit in the whole respiration pathway?
Stage
Location
Key products per glucose
Glycolysis
Cytoplasm
2 ATP (net) + 2 NADH
Link reaction
Mitochondrial matrix
2 NADH
Krebs cycle
Mitochondrial matrix
6 NADH + 2 FADH₂ + 2 GTP (≈2 ATP)
Oxidative phosphorylation
Inner mitochondrial membrane
≈30 ATP (from 10 NADH + 2 FADH₂)
2. Quick‑reference box – ATP yield
Expected ATP from one molecule of glucose (Cambridge value)
Substrate‑level phosphorylation: 4 ATP (2 from glycolysis, 2 GTP from Krebs).
Oxidative phosphorylation: ≈30 ATP (10 NADH × ≈2.5 ATP + 2 FADH₂ × ≈1.5 ATP).
Total ≈ 34 ATP – the syllabus quotes ≈30 ATP for the oxidative‑phosphorylation component.
3. The five key steps
Splitting of hydrogen atoms
Reduced co‑enzymes (NADH, FADH₂) each carry two hydrogen atoms.
When they donate their electrons, each hydrogen atom is separated into a proton (H⁺) and an energetic electron (e⁻).
Example: NADH → NAD⁺ + H⁺ + 2 e⁻
Electron transport chain (ETC)
Electrons pass “downhill” through a series of membrane‑embedded carriers (Complex I–IV, ubiquinone, cytochrome c).
Note: The Cambridge exam does not require naming each carrier – a generic description is sufficient.
As electrons move, they lose free energy because they move to carriers of lower redox potential.
Proton pumping & chemiosmotic gradient
The energy released in step 2 powers complexes I, III and IV to pump protons from the matrix into the inter‑membrane space.
This creates an electrochemical gradient (the proton‑motive force) across the inner membrane – the core of Peter Mitchell’s chemiosmotic hypothesis.
ATP synthesis (oxidative phosphorylation)
Protons flow back into the matrix through the enzyme ATP synthase (Complex V) by facilitated diffusion.
The flow drives conformational changes in ATP synthase that phosphorylate ADP + Pᵢ → ATP.
Final electron acceptor – oxygen
At Complex IV, electrons combine with molecular oxygen (O₂) and the protons that have been pumped back to form water (H₂O).
O₂ prevents a backup of electrons in the chain; without it the ETC would stop and ATP synthesis would cease.
4. Overall simplified reaction
NADH + H⁺ + ½ O₂ → NAD⁺ + H₂O + energy for ATP synthesis
5. Experimental evidence supporting the mechanism (AO3)
Uncouplers (e.g., dinitrophenol) – carry protons across the membrane, collapsing the gradient. ATP production falls dramatically while heat production rises, confirming that the gradient drives ATP synthesis.
Inhibitors:
Rotenone blocks Complex I → no NADH‑derived electrons → reduced ATP yield.
Cyanide or azide block Complex IV → electrons cannot be passed to O₂ → chain backs up, ATP synthesis stops.
Oligomycin blocks ATP synthase → protons cannot re‑enter the matrix → gradient builds up, electron flow slows, demonstrating the coupling of the gradient to ATP formation.
6. Practical skill linked to Paper 3 (AO3)
Design a simple investigation to test the effect of a respiratory inhibitor on mitochondrial ATP production:
Isolate mitochondria from fresh liver tissue (or use a commercial preparation).
Divide the suspension into two cuvettes – one control, one with a known concentration of cyanide.
Supply a substrate that generates NADH (e.g., pyruvate + NAD⁺) and measure ATP formed over time using a luciferase‑based luminescence assay.
Compare the rate of ATP synthesis between control and inhibited samples; a marked reduction confirms the role of the ETC and oxygen as the final electron acceptor.
7. Exam‑style practice question (AO2)
Question: Explain why molecular oxygen is essential for oxidative phosphorylation.
Answer outline (3‑4 marks):
O₂ acts as the final electron acceptor at Complex IV.
It combines with electrons and protons to form H₂O, removing electrons from the chain.
Removal of electrons allows the ETC to continue flowing “downhill”, keeping the proton pumps active.
Without O₂ the chain backs up, proton pumping stops, the proton‑motive force collapses, and ATP synthase can no longer produce ATP.
8. Summary table
Step
What happens
Energy outcome
1. Hydrogen‑atom split
H from NADH/FADH₂ → H⁺ + e⁻
Electrons carry high‑potential energy
2. Electron transport
e⁻ pass through ETC carriers
Energy released → drives proton pumps
3. Proton‑motive force
H⁺ pumped into inter‑membrane space
Electrochemical gradient stores energy
4. ATP synthesis
H⁺ flow back via ATP synthase
ADP + Pᵢ → ≈30 ATP (overall)
5. Oxygen as final acceptor
e⁻ + H⁺ + O₂ → H₂O
Prevents electron backup; completes the cycle
Suggested diagram: a schematic of the inner mitochondrial membrane showing the ETC complexes, proton pumping, the proton‑motive force, ATP synthase and O₂ as the final electron acceptor.
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