Recall and use the equation for resistance R = V / I

Published by Patrick Mutisya · 14 days ago

Cambridge IGCSE Physics 0625 – 4.2.4 Resistance

4.2.4 Resistance

Learning Objective

Recall and use the equation for resistance:

\$R = \frac{V}{I}\$

What is Resistance?

Resistance (\$R\$) is a property of a material that opposes the flow of electric current. It is measured in ohms (Ω). The higher the resistance, the less current will flow for a given voltage.

Key Relationships

  • Ohm’s Law: \$V = I R\$
  • Re‑arranged for resistance: \$R = \dfrac{V}{I}\$
  • Resistivity formula: \$R = \rho \dfrac{L}{A}\$ where

    • \$\rho\$ = resistivity of the material (Ω·m)
    • \$L\$ = length of the conductor (m)
    • \$A\$ = cross‑sectional area (m²)

Factors that Influence Resistance

  1. Material: Conductors (e.g., copper) have low resistivity; insulators have high resistivity.
  2. Length (\$L\$): Resistance is directly proportional to length.
  3. Cross‑sectional area (\$A\$): Resistance is inversely proportional to area.
  4. Temperature: For most metals, resistance increases with temperature.

Using the Equation \$R = \dfrac{V}{I}\$

To find any one of the three quantities (voltage, current, resistance) you need the other two.

Known QuantityFormula to Find UnknownExample
Voltage (\$V\$) and Current (\$I\$)\$R = \dfrac{V}{I}\$If \$V = 12\ \text{V}\$ and \$I = 3\ \text{A}\$, then \$R = 4\ \Omega\$.
Resistance (\$R\$) and Current (\$I\$)\$V = I R\$If \$R = 5\ \Omega\$ and \$I = 2\ \text{A}\$, then \$V = 10\ \text{V}\$.
Voltage (\$V\$) and Resistance (\$R\$)\$I = \dfrac{V}{R}\$If \$V = 9\ \text{V}\$ and \$R = 3\ \Omega\$, then \$I = 3\ \text{A}\$.

Worked Example

Problem: A copper wire 2.0 m long has a cross‑sectional area of \$1.0 \times 10^{-6}\ \text{m}^2\$. The resistivity of copper is \$1.68 \times 10^{-8}\ \Omega\!\cdot\!\text{m}\$. Calculate the resistance of the wire.

Solution:

  1. Write the resistivity formula: \$R = \rho \dfrac{L}{A}\$.
  2. Substitute the values:

    \$R = (1.68 \times 10^{-8}) \frac{2.0}{1.0 \times 10^{-6}}\$

  3. Calculate:

    \$R = (1.68 \times 10^{-8}) \times (2.0 \times 10^{6}) = 3.36 \times 10^{-2}\ \Omega\$

  4. Result: \$R = 0.0336\ \Omega\$ (approximately \$0.034\ \Omega\$).

Common Mistakes to Avoid

  • Confusing the symbols: \$V\$ is voltage, \$I\$ is current, \$R\$ is resistance.
  • Using the wrong units – always keep voltage in volts (V), current in amperes (A), resistance in ohms (Ω).
  • For the resistivity formula, ensure length and area are in metres (m) and square metres (m²) respectively.
  • Remember that \$R = V/I\$ only applies to ohmic (linear) conductors within their operating range.

Quick Revision Table

QuantitySymbolUnitFormula
Resistance\$R\$Ω (ohm)\$R = \dfrac{V}{I}\$
Voltage\$V\$V (volt)\$V = I R\$
Current\$I\$A (ampere)\$I = \dfrac{V}{R}\$
Resistivity\$\rho\$Ω·m\$R = \rho \dfrac{L}{A}\$

Suggested diagram: A simple circuit showing a battery, a resistor, an ammeter (in series) and a voltmeter (across the resistor). Label voltage \$V\$, current \$I\$, and resistance \$R\$.