recall and use I = I0e–μx for the attenuation of ultrasound in matter

Published by Patrick Mutisya · 14 days ago

Cambridge A-Level Physics 9702 – Production and Use of Ultrasound

Production and Use of Ultrasound

Learning Objective

Recall and use the attenuation relation

\$I = I_0 e^{-\mu x}\$

where I is the intensity after travelling a distance x in a material, I₀ is the initial intensity, and μ is the linear attenuation coefficient (m⁻¹).

1. What is Ultrasound?

Ultrasound refers to sound waves with frequencies above the upper limit of human hearing (≈20 kHz). In most A‑Level contexts the range is 0.5 MHz to 10 MHz.

2. Production of Ultrasound

  • Piezoelectric transducers – a crystal (e.g., quartz, PZT) deforms when an alternating voltage is applied, generating longitudinal waves. The same crystal can act as a receiver.
  • Magnetostrictive transducers – ferromagnetic rods change length in a varying magnetic field, producing sound.
  • Capacitive micromachined ultrasonic transducers (CMUTs) – a thin membrane vibrates under an electric field; used in high‑frequency imaging.

3. Key Properties of Ultrasound

PropertyTypical \cdot alue (A‑Level)Notes
Frequency (f)0.5 – 10 MHzHigher f → better resolution, greater attenuation
Wavelength (λ)0.15 – 3 mm (in water)λ = v/f, with v ≈ 1500 m s⁻¹ in soft tissue
Speed of sound (v)≈1500 m s⁻¹ in tissue, 340 m s⁻¹ in airDepends on medium density and elasticity

4. Attenuation of Ultrasound

The intensity of an ultrasonic beam decreases exponentially as it propagates through a material:

\$I(x) = I_0 e^{-\mu x}\$

Key points:

  • μ (linear attenuation coefficient) incorporates absorption and scattering.
  • Attenuation is frequency‑dependent; roughly μ ∝ f for many soft tissues.
  • In practice we often use the decibel form:

    \$\text{Loss (dB)} = 10 \log{10}\!\left(\frac{I0}{I}\right) = 8.686\,\mu x\$

Example Calculation

Given:

  • Initial intensity \$I_0 = 1.0\ \text{W m}^{-2}\$
  • Attenuation coefficient \$\mu = 0.5\ \text{m}^{-1}\$
  • Travel distance \$x = 3\ \text{cm} = 0.03\ \text{m}\$

Find the intensity after 3 cm.

Solution:

\$I = I_0 e^{-\mu x}=1.0\,e^{-0.5\times0.03}=1.0\,e^{-0.015}\approx 0.985\ \text{W m}^{-2}\$

The loss is small because the distance is short and μ is modest.

5. Uses of Ultrasound

  1. Medical imaging (sonography)

    • Pregnancy scans, abdominal organ imaging, Doppler flow measurement.
    • Resolution improves with higher frequency, but penetration depth decreases.

  2. Industrial non‑destructive testing (NDT)

    • Detect cracks, voids, and thickness variations in metals and composites.
    • Pulse‑echo and through‑transmission techniques rely on reflected intensity.

  3. Ultrasonic cleaning

    • High‑frequency cavitation removes contaminants from delicate parts.
    • Typical frequencies: 20–40 kHz (lower than imaging range).

  4. Sonochemistry

    • Acoustic cavitation drives chemical reactions, e.g., synthesis of nanoparticles.

6. Summary Checklist

  • Know the definition and units of the attenuation coefficient μ.
  • Be able to rearrange \$I = I_0 e^{-\mu x}\$ to solve for any variable.
  • Understand how frequency affects both resolution and attenuation.
  • Identify at least three practical applications of ultrasound and the typical frequency range used.

Suggested diagram: Schematic of a piezoelectric ultrasound transducer showing the alternating voltage, crystal vibration, and emitted longitudinal wave.