Published by Patrick Mutisya · 14 days ago
Describe melting and boiling in terms of energy input without a change in temperature.
When a substance undergoes a phase change, energy is absorbed (or released) but the temperature remains constant until the entire mass has changed phase. This is because the energy is used to overcome intermolecular forces rather than to increase kinetic energy.
The temperature at which a solid begins to melt is its melting point. At this temperature:
\$Q{\text{melt}} = mLf\$
where \$L_f\$ is the latent heat of fusion (J kg⁻¹).
Boiling occurs when a liquid reaches its boiling point. At this temperature:
\$Q{\text{boil}} = mLv\$
where \$L_v\$ is the latent heat of vapourisation (J kg⁻¹).
Evaporation is a surface phenomenon that can occur at any temperature below the boiling point. Unlike boiling, it does not require the whole liquid to reach a specific temperature. Energy is still required to overcome intermolecular forces, but the temperature of the remaining liquid may fall slightly because the most energetic molecules leave the surface.
| Aspect | Melting | Boiling | Evaporation |
|---|---|---|---|
| Phase change | Solid → Liquid | Liquid → Gas (throughout) | Liquid → Gas (surface only) |
| Temperature during change | Constant at melting point | Constant at boiling point | May decrease slightly; no fixed temperature |
| Energy required | \$Q = mL_f\$ | \$Q = mL_v\$ | Variable; related to \$L_v\$ but less than bulk boiling |
| Typical latent heat values (for water) | \$L_f = 3.34 \times 10^5\ \text{J kg}^{-1}\$ | \$L_v = 2.26 \times 10^6\ \text{J kg}^{-1}\$ | ≈ \$L_v\$ for molecules that escape |
How much energy is needed to melt 250 g of ice at 0 °C?
Given \$L_f = 3.34 \times 10^5\ \text{J kg}^{-1}\$:
\$Q = mL_f = 0.250\ \text{kg} \times 3.34 \times 10^5\ \text{J kg}^{-1} = 8.35 \times 10^4\ \text{J}\$
The temperature of the ice remains at 0 °C until the entire 250 g has melted.