calculate RQ values of different respiratory substrates from equations for respiration

Energy – Respiratory Quotient (RQ)

Quick‑reference RQ values (typical)

  • Carbohydrate (e.g. glucose, fructose)  RQ = 1.00
  • Fat (e.g. palmitic, oleic acid)     RQ ≈ 0.70 – 0.71
  • Protein (average whole‑protein mixture) RQ ≈ 0.80 – 0.90


    – the exact value varies with the proportion of nitrogen excreted as urea (humans) or ammonia (many animals).

  • Mixed diet (≈ 60 % carb, 30 % fat, 10 % protein) RQ ≈ 0.85

What is RQ? (AO1)

The respiratory quotient (RQ) is the ratio of carbon dioxide produced to oxygen consumed during aerobic cellular respiration:

\[

\text{RQ} = \frac{\text{moles of CO}2\text{ produced}}{\text{moles of O}2\text{ consumed}}

\]

It is a dimension‑less number that reveals which class of substrate (carbohydrate, lipid or protein) is being oxidised.

Why RQ matters in A‑Level Biology (AO1, AO2, AO3)

  • Identifies the predominant respiratory substrate in a physiological or experimental situation.
  • Enables interpretation of indirect calorimetry data (exercise physiology, clinical nutrition).
  • Links substrate utilisation to ATP yield – a lower RQ generally means more ATP per mole of O₂ used (fat oxidation).

General method for calculating RQ (AO2)

  1. Write the balanced aerobic oxidation equation for the substrate.
  2. Read the stoichiometric coefficient of CO₂ (numerator).
  3. Read the stoichiometric coefficient of O₂ (denominator).
  4. Divide CO₂ mol by O₂ mol and simplify.

Balanced oxidation equations (AO1)

Substrate typeRepresentative moleculeBalanced aerobic oxidation equationCO₂ (mol)O₂ (mol)RQ
CarbohydrateGlucose (C₆H₁₂O₆)\(\mathrm{C6H{12}O6 + 6\,O2 \rightarrow 6\,CO2 + 6\,H2O}\)661.00
Lipid (fatty acid)Palmitic acid (C₁₆H₃₂O₂)\(\mathrm{C{16}H{32}O{2} + 23\,O2 \rightarrow 16\,CO2 + 16\,H2O}\)16230.70
Protein (average whole‑protein mixture)Alanine (C₃H₇NO₂) – illustrative\(\mathrm{C3H7NO2 + 2.5\,O2 \rightarrow 3\,CO2 + 2.5\,H2O + NH_3}\)32.51.20\;(\text{single amino‑acid only})
Mixed diet (average of carbs, fats & proteins)≈ 0.85 × O₂ consumed≈ 0.85

Note: Whole‑protein oxidation does not give a single RQ; the value depends on how nitrogen is excreted. In humans most nitrogen leaves as urea, giving an overall protein RQ of ~0.80–0.90, whereas in many laboratory animals ammonia excretion pushes the value slightly higher.

Worked examples (AO2)

1. RQ for palmitic acid

  1. Equation: \(\mathrm{C{16}H{32}O{2} + 23\,O2 \rightarrow 16\,CO2 + 16\,H2O}\)
  2. CO₂ = 16 mol, O₂ = 23 mol
  3. \(\displaystyle \text{RQ}= \frac{16}{23}=0.70\) (2 dp)

2. RQ for oleic acid (C₁₈H₃₄O₂)

\[

\mathrm{C{18}H{34}O{2} + 25.5\,O2 \rightarrow 18\,CO2 + 17\,H2O}

\]

\[

\text{RQ}= \frac{18}{25.5}=0.71

\]

3. Converting gas volumes to moles (ideal‑gas example)

In a respirometer the following changes are recorded after 10 min at 298 K and 1 atm:

  • ΔVO₂ = 0.025 L (decrease)
  • ΔVCO₂ = 0.020 L (increase, after CO₂ is not absorbed)

Using the ideal‑gas equation \(PV = nRT\) (R = 0.0821 L·atm·K⁻¹·mol⁻¹):

\[

n{\mathrm{O2}} = \frac{P\,V}{R\,T}= \frac{1.00\;\text{atm}\times0.025\;\text{L}}{0.0821\;\text{L·atm·K}^{-1}\text{mol}^{-1}\times298\;\text{K}} = 1.02\times10^{-3}\;\text{mol}

\]

\[

n{\mathrm{CO2}} = \frac{1.00\times0.020}{0.0821\times298}=8.15\times10^{-4}\;\text{mol}

\]

\[

\text{RQ}= \frac{8.15\times10^{-4}}{1.02\times10^{-3}}=0.80\;(2\;\text{dp})

\]

The experimental RQ of 0.80 suggests a mixed utilisation of carbohydrate and fat.

Link between RQ and ATP yield (AO3)

  • Glucose → ≈ 30 ATP per molecule; RQ = 1.00.
  • Palmitic acid → ≈ 106 ATP per molecule; RQ ≈ 0.70 (more O₂ required per CO₂, so more ATP per O₂).
  • Protein (average) → ≈ 21 ATP per amino‑acid residue after deamination; RQ ≈ 0.80‑0.90.

Thus a lower RQ generally indicates a substrate that yields more ATP per mole of O₂, which explains why fat oxidation predominates during prolonged, low‑intensity exercise.

Practical investigation: Determining RQ with a simple respirometer (AO4)

  1. Place 5 g of germinating beans in a sealed syringe‑type respirometer containing a known volume of air (≈ 30 mL).
  2. Connect one outlet to a soda‑lime tube (absorbs CO₂) and the other to a water‑filled graduated tube to record volume changes.
  3. Incubate at a constant temperature (e.g. 25 °C) for a fixed period (10 min).
  4. Read the decrease in O₂ volume (ΔVO₂) and the increase in CO₂ volume (ΔVCO₂) after the period.
  5. Convert each volume to moles using \(n = PV/RT\) (show all substitutions).
  6. Calculate RQ = nCO₂ / nO₂.

Sample calculation (using the data from the ideal‑gas example above)

  1. For O₂: \(n = \dfrac{1.00\times0.025}{0.0821\times298}=1.02\times10^{-3}\;\text{mol}\)
  2. For CO₂: \(n = \dfrac{1.00\times0.020}{0.0821\times298}=8.15\times10^{-4}\;\text{mol}\)
  3. RQ = \(8.15\times10^{-4}/1.02\times10^{-3}=0.80\)

Error‑analysis table (AO4)

Potential source of errorEffect on measured ΔVO₂ or ΔVCO₂Resulting bias in RQ
Leakage of the respirometerBoth O₂ loss and CO₂ escape are underestimated.RQ may be either higher or lower depending on which gas leaks more.
Incomplete CO₂ absorption by soda‑limeΔVCO₂ appears larger than true.RQ is over‑estimated (suggests more carbohydrate).
Temperature drift (affects gas volume)Volumes recorded at a temperature different from the one used in the PV = nRT calculation.Systematic error in both n values → RQ may be inaccurate.
Calibration error of the graduated tubeSystematic over‑ or under‑reading of volumes.Bias proportional to the direction of mis‑calibration.

Mixed‑diet RQ calculation (AO2)

If a diet supplies 60 % carbohydrate, 30 % fat and 10 % protein (by oxidised energy), the overall RQ is the weighted average of the individual RQs:

\[

\text{RQ}_{\text{mix}} = 0.60(1.00) + 0.30(0.70) + 0.10(0.85) \approx 0.85

\]

This matches the “average” value quoted for a typical human mixed diet.

Key points to remember (AO1)

  • Carbohydrates give RQ = 1.00 (1 mol CO₂ per 1 mol O₂).
  • Fats give a lower RQ (≈ 0.70) because they contain more reduced carbon and need more O₂ per CO₂.
  • Protein RQ is not fixed; whole‑protein mixtures give ≈ 0.80‑0.90, influenced by nitrogen excretion (urea vs. ammonia).
  • Mixed diets yield an intermediate RQ (~0.85), reflecting the proportion of each substrate.
  • RQ is linked to ATP yield – lower RQ → more ATP per mole of O₂.

Practice questions

  1. Fructose has the same empirical formula as glucose (C₆H₁₂O₆). Calculate its RQ.

    Answer: 1.00 (same balanced equation as glucose).

  2. Oxidation of oleic acid (C₁₈H₃₄O₂): \(\mathrm{C{18}H{34}O{2} + 25.5\,O{2} \rightarrow 18\,CO{2} + 17\,H{2}O}\). Determine the RQ.

    Solution: RQ = 18 / 25.5 ≈ 0.71.

  3. In a respirometer experiment, 0.030 mol O₂ are consumed and 0.025 mol CO₂ are produced. What substrate(s) are most likely being oxidised?

    Hint: Experimental RQ = 0.83 – compare with textbook values (carb = 1.00, fat ≈ 0.70, protein ≈ 0.80‑0.90).

    Answer: Predominantly a mixed utilisation of carbohydrate and fat, with a small protein contribution.

Assessment Objective (AO) alignment

  • AO1 – Knowledge: Define RQ, list typical RQ values (quick‑reference box), write balanced oxidation equations for carbohydrate, lipid, protein (including note on variability) and mixed diet.
  • AO2 – Application: Calculate RQ from given equations, perform unit‑conversion using the ideal‑gas law, compute mixed‑diet RQ, interpret respirometer data.
  • AO3 – Analysis: Explain why different substrates give different RQ values and relate RQ to ATP yield per mole of O₂.
  • AO4 – Evaluation: Design a simple experiment to measure RQ, show a full worked calculation, and evaluate sources of error (error‑analysis table).