Published by Patrick Mutisya · 14 days ago
Represent α‑ and β‑decay by a radioactive decay equation of the form \$\,{Z}^{A}\text{X} \rightarrow \,{Z'}^{A'}\text{Y} + \text{particle}\,\$.
In α‑decay the nucleus emits an α‑particle, which is a helium‑4 nucleus:
\$\$
\,{92}^{238}\text{U} \;\rightarrow\; \,{90}^{234}\text{Th} \;+\; \,_{2}^{4}\alpha
\$\$
In β‑decay a neutron is transformed into a proton with the emission of an electron (β⁻ particle) and an antineutrino (often omitted in simple equations):
\$\$
\,{6}^{14}\text{C} \;\rightarrow\; \,{7}^{14}\text{N} \;+\; \,_{-1}^{0}\beta
\$\$
| Feature | α‑Decay | β‑Decay |
|---|---|---|
| Particle emitted | α‑particle (\$\,_{2}^{4}\alpha\$) | β⁻ particle (\$\,_{-1}^{0}\beta\$) |
| Change in mass number (A) | ‑4 | 0 |
| Change in atomic number (Z) | ‑2 | +1 |
| Typical energy released | \overline{4}–9 MeV | \overline{0}.5–2 MeV |