Published by Patrick Mutisya · 14 days ago
Explain the advantages of connecting lamps in parallel in a lighting circuit.
\$I{\text{total}} = \sum{k=1}^{n} I_k\$
\$\frac{1}{R{\text{eq}}}= \sum{k=1}^{n}\frac{1}{R_k}\$
Each lamp receives the full supply voltage, so all lamps glow with the same intensity. In a series circuit the voltage is divided, causing dimmer lamps further from the source.
If one lamp fails (opens), the other lamps continue to operate because each has its own branch. In series, a single failure interrupts the whole circuit.
Switches or dimmers can be placed on individual branches without affecting other lamps.
Lower equivalent resistance reduces the overall current drawn for a given power requirement, minimising heating in conductors.
| Feature | Series Connection | Parallel Connection |
|---|---|---|
| Voltage across each lamp | Divides among lamps (\$V{\text{lamp}} = V{\text{total}}/n\$) | Same as source voltage (\$V{\text{lamp}} = V{\text{source}}\$) |
| Current through each lamp | Same current flows through all lamps | Current varies with lamp resistance; total current is sum of branch currents |
| Effect of a lamp failure | All lamps go out (open circuit) | Only the failed lamp goes out; others stay lit |
| Brightness uniformity | Often uneven; lamps farther from source may be dimmer | Uniform brightness for all lamps |
| Equivalent resistance | \$R_{\text{eq}} = nR\$ (higher) | \$\displaystyle\frac{1}{R{\text{eq}}}= \sum\frac{1}{Rk}\$ (lower) |
Consider three identical 60 W, 240 V lamps.
Each lamp has a resistance \$R = \dfrac{V^2}{P} = \dfrac{240^2}{60} = 960\ \Omega\$.
Series connection:
Parallel connection: