Published by Patrick Mutisya · 14 days ago
Define gravitational potential at a point as the work done per unit mass in bringing a small test mass from infinity to that point.
Consider a test mass \$m\$ moving radially towards a point at distance \$r\$ from a mass \$M\$.
\$\$
W = -\int{\infty}^{r} \frac{GMm}{r^{2}}\,dr = -GMm\left[-\frac{1}{r}\right]{\infty}^{r}= -\frac{GMm}{r}.
\$\$
The work done per unit mass is therefore
\$\$
\phi(r)=\frac{W}{m}= -\frac{GM}{r}.
\$\$
This quantity \$\phi(r)\$ is defined as the gravitational potential at distance \$r\$ from the mass \$M\$.
| Symbol | Quantity | Unit |
|---|---|---|
| \$G\$ | Universal gravitational constant | 6.674 × 10⁻¹¹ N m² kg⁻² |
| \$M\$ | Mass producing the field | kg |
| \$m\$ | Test mass | kg |
| \$r\$ | Distance from the centre of \$M\$ | m |
| \$\phi\$ | Gravitational potential | J kg⁻¹ |
| \$U\$ | Gravitational potential energy | J |
Calculate the gravitational potential at the surface of the Earth (radius \$R{\oplus}=6.37\times10^{6}\,\text{m}\$, mass \$M{\oplus}=5.97\times10^{24}\,\text{kg}\$).
\$\$
\phi{\oplus}= -\frac{GM{\oplus}}{R_{\oplus}} \approx -\frac{6.674\times10^{-11}\times5.97\times10^{24}}{6.37\times10^{6}} \approx -6.3\times10^{7}\,\text{J kg}^{-1}.
\$\$
This negative value indicates that work must be done against the Earth's gravity to move a unit mass from the surface to infinity.
Gravitational potential \$\phi\$ at a point is defined as the work done per unit mass in bringing a test mass from infinity to that point, expressed as \$\phi = -GM/r\$. It provides a convenient scalar description of the gravitational field and forms the basis for calculating potential energy, orbital mechanics, and energy considerations in astrophysics.