Published by Patrick Mutisya · 14 days ago
Understand that a resistive force acting on an oscillating system causes damping, and explore the consequences for natural and forced oscillations.
For an undamped mass‑spring system the equation of motion is
\$m\ddot{x}+kx=0\$
with solution \$x(t)=A\cos(\omega0 t+\phi)\$ where \$\omega0=\sqrt{k/m}\$.
A resistive force proportional to the velocity, \$F_{\text{d}}=-b\dot{x}\$, is common in real systems (air resistance, internal friction, electrical resistance in an RLC circuit). Adding this term gives the damped equation of motion
\$m\ddot{x}+b\dot{x}+kx=0\$
where \$b\$ is the damping coefficient (units kg s⁻¹).
| Condition | Relation of \$b\$ to \$2\sqrt{mk}\$ | Behaviour |
|---|---|---|
| Underdamped | \$b<2\sqrt{mk}\$ | Oscillatory motion with exponentially decaying amplitude. |
| Critically damped | \$b=2\sqrt{mk}\$ | Returns to equilibrium as quickly as possible without overshoot. |
| Overdamped | \$b>2\sqrt{mk}\$ | Non‑oscillatory return to equilibrium, slower than critical. |
Define the damping ratio \$\zeta =\dfrac{b}{2\sqrt{mk}}\$ and the damped angular frequency \$\omegad = \omega0\sqrt{1-\zeta^2}\$.
The displacement is
\$x(t)=A e^{-\zeta\omega0 t}\cos(\omegad t+\phi)\$
The amplitude decays as \$A(t)=A e^{-\zeta\omega_0 t}\$, illustrating how the resistive force reduces the oscillation amplitude over time.
The mechanical energy of the oscillator is
\$E(t)=\frac{1}{2}kA^2 e^{-2\zeta\omega_0 t}\$
Because the damping force does negative work, energy is continuously removed from the system at a rate
\$\frac{dE}{dt} = -b\dot{x}^2\$
When an external periodic driving force \$F{\text{ext}} = F0\cos(\omega t)\$ acts on the damped system, the equation becomes
\$m\ddot{x}+b\dot{x}+kx = F_0\cos(\omega t)\$
The steady‑state (particular) solution is
\$x(t)=X(\omega)\cos(\omega t - \delta)\$
with amplitude
\$X(\omega)=\frac{F0/m}{\sqrt{(\omega0^2-\omega^2)^2+(2\zeta\omega_0\omega)^2}}\$
and phase lag
\$\tan\delta = \frac{2\zeta\omega0\omega}{\omega0^2-\omega^2}\$