Published by Patrick Mutisya · 14 days ago
Apply the intensity reflection coefficient formula
\$\frac{IR}{I0}= \frac{(Z1-Z2)^2}{(Z1+Z2)^2}\$
to analyse how ultrasound behaves at the interface between two media.
Ultrasound refers to sound waves with frequencies above the upper limit of human hearing (≈20 kHz). In medical and industrial applications frequencies typically lie between 1 MHz and 15 MHz, giving wavelengths of a few millimetres to a few hundred micrometres in soft tissue.
All these devices rely on the rapid conversion of electrical energy into mechanical vibrations, which then propagate as ultrasound.
The speed of sound \$v\$ in a medium is given by
\$v=\sqrt{\frac{B}{\rho}}\$
where \$B\$ is the bulk modulus and \$\rho\$ the density. The acoustic impedance \$Z\$ is defined as
\$Z = \rho v\$
Differences in \$Z\$ between adjoining media cause part of the incident wave to be reflected and part to be transmitted.
When an ultrasound wave of intensity \$I0\$ strikes a planar boundary between medium 1 (impedance \$Z1\$) and medium 2 (impedance \$Z2\$), the reflected intensity \$IR\$ is
\$\frac{IR}{I0}= \frac{(Z1-Z2)^2}{(Z1+Z2)^2}\$
This expression follows from matching pressure and particle‑velocity boundary conditions and is central to both imaging (e.g., echocardiography) and non‑destructive testing.
Consider an ultrasound pulse travelling from soft tissue (\$Z{\text{tissue}}\approx1.6\times10^6\ \text{kg m}^{-2}\text{s}^{-1}\$) into bone (\$Z{\text{bone}}\approx7.8\times10^6\ \text{kg m}^{-2}\text{s}^{-1}\$).
About 44 % of the incident intensity is reflected at the tissue–bone interface, which explains the bright echo seen in an abdominal scan.
| Medium | Density \$\rho\$ (kg m⁻³) | Speed of sound \$v\$ (m s⁻¹) | Acoustic impedance \$Z\$ (kg m⁻² s⁻¹) |
|---|---|---|---|
| Air | 1.2 | 340 | 4.1 × 10⁻¹ |
| Water | 1000 | 1480 | 1.48 × 10⁶ |
| Soft tissue | 1060 | 1540 | 1.63 × 10⁶ |
| Bone | 1900 | 4100 | 7.79 × 10⁶ |
| Aluminium | 2700 | 6420 | 1.73 × 10⁷ |
To reduce the large reflection at a high‑impedance–low‑impedance interface, a thin matching layer with impedance \$Zm\approx\sqrt{Z1Z_2}\$ is placed between the transducer and the load. The thickness is usually a quarter of the wavelength in the matching material, giving destructive interference for the reflected wave and constructive interference for the transmitted wave.