\Delta m = \bigl[ Z\,m{p}+ (A-Z)\,m{n}\bigr] - m_{\text{atom}}
\]
\[
E_{b}= \Delta m \times 931.5\;\text{MeV}
\qquad\qquad
\frac{E{b}}{A}= \frac{E{b}}{A}
\]
with \(m{p}=1.007276\;\text{u}\) and \(m{n}=1.008665\;\text{u}\).
Selected data (mass defect, binding energy and binding energy per nucleon)
Nuclide \({}^{A}_{Z}\!X\)
A
Δm (u)
Eb (MeV)
Eb/A (MeV)
\({}^{2}_{1}\!H\) (deuterium)
2
0.0022
2.05
1.02
\({}^{4}_{2}\!He\) (α‑particle)
4
0.0304
28.3
7.07
\({}^{12}_{6}\!C\)
12
0.0985
92.2
7.68
\({}^{16}_{8}\!O\)
16
0.1365
127.6
7.98
\({}^{56}_{26}\!Fe\)
56
0.4920
492.3
8.79
\({}^{62}_{28}\!Ni\)
62
0.5436
534.4
8.79 (≈8.794)
\({}^{238}_{92}\!U\)
238
1.7840
1664.0
7.00
Variation of binding‑energy‑per‑nucleon with nucleon number
The curve of \(E_{b}/A\) against \(A\) has a characteristic “mountain‑range” shape. The sketch below includes the key points required by the Cambridge 9702 syllabus.
Nucleon number \(A\)
Binding energy per nucleon (MeV)
20
40
60
80
100
120
140
160
6
7
8
9
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\(A\approx20\)
Peak (Fe‑56, Ni‑62)
\(A\approx200\)
Features of the curve
Rapid rise (A ≲ 20) – Adding a nucleon creates many new short‑range attractive pairs, while a large fraction of nucleons are still on the surface.
Broad maximum (A ≈ 56–62) – The most tightly bound nuclei are \({}^{56}{26}\!Fe\) and \({}^{62}{28}\!Ni\) (≈ 8.79 MeV per nucleon). Here the gain from extra nuclear attraction is almost cancelled by the growing Coulomb repulsion.
Gradual decline (A > 62) – Electrostatic repulsion between the increasing number of protons outweighs the additional nuclear force, so \(E_{b}/A\) falls to ≈ 7 MeV for the actinides.
Physical interpretation (why the curve has this shape)
Short‑range nuclear force – Each nucleon feels a strong attractive force only from its nearest neighbours. In very light nuclei many nucleons are on the surface and have fewer neighbours, giving a low \(E_{b}/A\).
Surface effect – The surface‑to‑volume ratio decreases as \(A\) grows, so the proportion of “unbound” surface nucleons falls, raising the average binding.
Electrostatic (Coulomb) repulsion – The repulsive energy grows roughly as \(Z^{2}\) and becomes dominant for heavy nuclei, pulling the curve down.
Stability – Nuclei near the peak are the most stable. Nuclei left of the peak can release energy by fusing (moving toward higher \(E_{b}/A\)); nuclei right of the peak can release energy by fissioning into fragments that lie nearer the peak.
\({}^{12}{6}\!C\), \({}^{16}{8}\!O\) (and heavier nuclei up to Fe‑group)
~7 MeV per nucleon added
Fission
\({}^{235}{92}\!U\), \({}^{239}{94}\!Pu\)
Two fragments with \(A\approx 90–150\) (e.g. \({}^{144}{56}\!Ba\) + \({}^{89}{36}\!Kr\))
~0.9 MeV per nucleon gained
Exam‑style tip
When asked to “sketch the variation of \(E_{b}/A\) with \(A\)”, remember the three labelled points:
Rapid rise up to \(A\approx20\)
Maximum at \(A\approx56\)–\(62\) (Fe‑56, Ni‑62)
Slow decline for \(A>62\) (≈ 7 MeV for uranium).
To compare fusion and fission, state which side of the curve the reactants lie on and which side the products lie on; the movement towards the peak indicates energy release.
Use the conversion \(1\;\text{u}=931.5\;\text{MeV}\) whenever you turn a mass defect into an energy value.
Summary
The binding‑energy‑per‑nucleon curve summarises the competition between the short‑range attractive nuclear force and the long‑range Coulomb repulsion. Its maximum near \({}^{62}{28}\!Ni\) explains why both fusion (for light nuclei) and fission (for heavy nuclei) can release energy: the products occupy a higher point on the curve, i.e. they have a larger \(E{b}/A\) and therefore a lower total mass‑energy.
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