Passage of Information from Parents to Offspring
Learning Objectives (AO1)
- Define haploid (n) and diploid (2n) and explain their significance in sexual reproduction.
- Describe the flow of genetic information: DNA → RNA → protein.
- Apply Mendelian principles (monohybrid, dihybrid, test‑crosses) and explain how meiosis generates genetic variation.
- Interpret pedigrees, recognise sex‑linked inheritance and understand genetic linkage.
- Explain how genetic variation provides material for natural selection and evolution.
Key Points – Mapping to the Cambridge Syllabus
| Syllabus Topic |
What you must be able to do (AO1) |
| 6.1 – Structure of nucleotides & DNA |
Describe the structure of a nucleotide and the double‑helix model of DNA. |
| 6.2 – DNA replication |
Explain semi‑conservative replication and name the main enzymes (DNA polymerase, helicase, ligase). |
| 6.3 – Gene expression |
Outline transcription and translation, naming RNA polymerase and the role of ribosomes. |
| 17.1 – Mendelian inheritance |
Predict genotype and phenotype ratios for monohybrid and dihybrid crosses; use test‑crosses. |
| 17.2 – Sex‑linked traits & pedigrees |
Analyse X‑linked inheritance patterns and construct simple pedigrees. |
| 17.3 – Linkage & recombination |
Explain how linked genes affect ratios and calculate map distance. |
| 17.4 – Polygenic & quantitative traits |
Describe traits controlled by many genes and how they appear in pedigrees. |
| 18 – Natural selection & evolution |
Discuss how variation generated by meiosis and mutation provides raw material for selection. |
1. Chromosome Numbers and Ploidy
| Cell / Organism |
Chromosome Number |
Notation |
Ploidy |
| Human somatic cell (e.g., skin fibroblast) |
46 |
2n |
Diploid |
| Human sperm (male gamete) |
23 |
n |
Haploid |
| Human egg (female gamete) |
23 |
n |
Haploid |
| Human zygote (fertilised egg) |
46 |
2n |
Diploid |
Haploid (n): a cell that contains one complete set of chromosomes (e.g., human gametes, n = 23).
Diploid (2n): a cell that contains two complete sets of chromosomes, one inherited from each parent (e.g., human somatic cells, 2n = 46).
2. Meiosis – Production of Haploid Gametes
Meiosis reduces the chromosome number from 2n to n and introduces genetic diversity through crossing‑over and independent assortment.
2.1 Overview of the Two Divisions
- Meiosis I – Reductional Division
- Prophase I – Homologous chromosomes pair (synapsis) and exchange non‑sister chromatids (crossing‑over).
- Metaphase I – Paired homologues line up on the metaphase plate; orientation is random (independent assortment).
- Anaphase I – Homologous chromosomes separate to opposite poles.
- Telophase I & Cytokinesis – Two haploid cells form, each still containing sister chromatids.
- Meiosis II – Equational Division
- Resembles mitosis: sister chromatids separate, giving four genetically distinct haploid gametes.
2.2 Key Outcomes of Meiosis
- Halving of chromosome number (2n → n).
- Genetic recombination via crossing‑over.
- Independent assortment of maternal and paternal chromosomes.
- Production of four non‑identical haploid gametes.
2.3 Genetic Linkage & Recombination (Syllabus Topic 17.3)
- Genes that are close together on the same chromosome tend to be inherited together – linked genes.
- Crossing‑over can separate linked genes; the frequency of recombination (cM) reflects the physical distance:
Map distance (cM) = (Number of recombinant offspring ÷ Total offspring) × 100.
- In a test‑cross (linked heterozygote × recessive homozygote) the observed ratios deviate from the 9:3:3:1 pattern and allow calculation of map distance.
3. Fertilisation – Restoration of Diploidy
Fusion of a haploid sperm (n) with a haploid egg (n) restores the diploid chromosome complement:
2n = nsperm + negg
The resulting zygote contains one set of chromosomes from each parent and will undergo mitotic divisions to form the embryo.
4. Flow of Genetic Information (DNA → RNA → Protein)
4.1 DNA Structure
- Double helix of two antiparallel strands.
- Each strand is a polymer of nucleotides (sugar‑phosphate backbone + nitrogenous base).
- Base‑pairing: A↔T (2 H‑bonds), G↔C (3 H‑bonds).
4.2 DNA Replication (Semi‑conservative)
- Helicase unwinds the double helix.
- RNA primase synthesises short RNA primers (often omitted in syllabus – simply “RNA primer”).
- DNA polymerase adds nucleotides to the 3’ end (continuous synthesis on the leading strand, discontinuous on the lagging strand).
- DNA ligase joins Okazaki fragments on the lagging strand.
4.3 Transcription (DNA → mRNA)
- RNA polymerase binds to the promoter region of a gene.
- RNA strand is synthesised 5’→3’ using the antisense DNA strand as template.
- In eukaryotes the primary transcript is processed:
- 5’ capping
- Splicing to remove introns
- Poly‑A tail addition
4.4 Translation (mRNA → Polypeptide)
- Ribosome binds to the start codon (AUG) on mature mRNA.
- tRNA molecules deliver specific amino acids; the anticodon pairs with the codon.
- Peptide bonds form as the ribosome moves along the mRNA (elongation).
- Translation stops at a stop codon (UAA, UAG, UGA); the polypeptide is released and folds into a functional protein.
5. Mendelian Inheritance (Topic 17.1)
5.1 Fundamental Concepts
- Gene – unit of inheritance located on a chromosome.
- Allele – alternative form of a gene.
- Genotype – genetic makeup (e.g., AA, Aa, aa).
- Phenotype – observable trait.
- Dominant allele masks the effect of a recessive allele in a heterozygote.
- Co‑dominance, incomplete dominance and polygenic inheritance extend the simple dominant‑recessive model (see Section 7).
5.2 Monohybrid Cross
Cross between individuals that differ in a single trait (e.g., Rr × Rr).
| Parental Genotype | Gametes Produced |
| Rr | R, r |
Resulting Punnett square gives a 3:1 phenotypic ratio (dominant : recessive) and a 1:2:1 genotypic ratio.
5.3 Dihybrid Cross
Two traits are considered simultaneously (e.g., RrYy × RrYy).
Assuming independent assortment, the expected phenotypic ratio is 9 : 3 : 3 : 1.
5.4 Test‑Cross
Cross a homozygous recessive individual (aa) with an individual of unknown genotype.
- If all offspring show the dominant phenotype → unknown parent is homozygous dominant (AA).
- If both phenotypes appear in a 1:1 ratio → unknown parent is heterozygous (Aa).
5.5 Sex‑Linked Inheritance (X‑linked)
- Genes located on the X chromosome (e.g., haemophilia, red‑green colour blindness).
- Male (XY) expresses a recessive X‑linked allele because there is no second X to mask it.
- Typical pedigree pattern: vertical transmission, affected males, carrier females (half‑filled circles).
5.6 Pedigree Analysis (Topic 17.2)
- Symbols: square = male, circle = female, filled = affected, half‑filled = carrier (for recessive X‑linked).
- Steps:
- Identify the mode of inheritance (autosomal dominant, autosomal recessive, X‑linked).
- Determine the genotype of each individual where possible.
- Calculate probabilities for future offspring.
6. Polygenic & Quantitative Traits (Topic 17.4)
- Traits controlled by many genes, each contributing a small effect (e.g., human height, skin colour, milk yield in cattle).
- Phenotypic distribution is continuous and approximates a normal curve.
- In pedigrees polygenic traits appear as a range of phenotypes rather than discrete categories; they are often analysed with statistical methods rather than simple Punnett squares.
7. Genetic Variation and Evolution (Topic 18)
- Sources of variation:
- Meiotic crossing‑over and independent assortment.
- Genetic linkage and recombination.
- Mutations (point, insertion, deletion, chromosomal rearrangements).
- Natural selection acts on phenotypic variation; advantageous genotypes increase in frequency over generations.
- Example – Sickle‑cell allele (HbS): heterozygotes (HbA/HbS) are resistant to malaria, illustrating balanced polymorphism.
8. Abnormal Ploidy and Clinical Relevance
- Triploidy (3n) – usually lethal; embryos fail to develop.
- Down syndrome (Trisomy 21) – extra chromosome 21 (2n + 1); results in characteristic developmental features.
- Turner syndrome (45,X) – monosomy of a sex chromosome; short stature, infertility.
- Klinefelter syndrome (47,XXY) – extra X chromosome in males; reduced fertility, tall stature.
9. Summary
- Haploid (n) cells contain one complete set of chromosomes; diploid (2n) cells contain two sets.
- Meiosis creates haploid gametes and introduces variation through crossing‑over, independent assortment and recombination of linked genes.
- Fertilisation restores diploidy, producing a genetically unique zygote.
- DNA stores genetic information; it is replicated, transcribed into RNA, and translated into proteins.
- Mendelian principles (monohybrid, dihybrid, test‑cross) predict inheritance of single‑gene traits; sex‑linked patterns are traced with pedigrees.
- Linkage modifies expected ratios and allows calculation of map distances; polygenic traits produce continuous variation.
- Variation generated by meiosis and mutation provides the raw material for natural selection and evolution.
Suggested Diagrams for Classroom Use
- Chromosome complement in haploid vs. diploid cells (human example).
- Detailed stages of Meiosis I and Meiosis II, highlighting crossing‑over and independent assortment.
- Linkage map showing recombination frequencies and a test‑cross analysis.
- Flowchart of DNA replication, transcription and translation (with syllabus‑approved enzyme names).
- Punnett squares for monohybrid and dihybrid crosses.
- Pedigree chart illustrating an X‑linked recessive trait.
- Histogram of a polygenic trait (e.g., human height) showing normal distribution.
- Illustration of natural selection acting on a population with a sickle‑cell allele.