Understand how a Hall probe can be used to measure the magnetic flux density $B$ in a region where a conductor carrying current $I$ experiences a magnetic force.
The magnetic force on a straight conductor of length $L$ carrying a current $I$ in a uniform magnetic field $\mathbf{B}$ is given by the Lorentz force law:
$$\mathbf{F}=I\,\mathbf{L}\times\mathbf{B}$$For a conductor oriented perpendicular to the field, the magnitude simplifies to:
$$F = I L B \sin\theta$$where $\theta$ is the angle between $\mathbf{L}$ and $\mathbf{B}$. When $\theta = 90^{\circ}$, $\sin\theta = 1$ and $F = I L B$.
When a current $I_{\text{H}}$ flows through a thin semiconductor plate placed in a magnetic field $B$, charge carriers experience a magnetic force that drives them to one side of the plate, creating a transverse voltage $V_{\text{H}}$ – the Hall voltage.
The Hall voltage is related to the magnetic flux density by:
$$V_{\text{H}} = \frac{I_{\text{H}} B}{n q t}$$where:
Rearranging gives the magnetic flux density:
$$B = \frac{V_{\text{H}} n q t}{I_{\text{H}}}$$A Hall probe incorporates a calibrated Hall sensor and electronics that output $B$ directly, but the underlying principle follows the equation above. The steps are:
The following method links the measured $B$ to the magnetic force on a conductor.
Given:
| Quantity | Symbol | Value | Unit |
|---|---|---|---|
| Current through the wire | $I$ | 2.5 | A |
| Length of wire in field | $L$ | 0.150 | m |
| Magnetic flux density (Hall probe reading) | $B$ | 0.035 | T |
Force:
$$F = I L B = (2.5\ \text{A})(0.150\ \text{m})(0.035\ \text{T}) = 0.0131\ \text{N}$$By measuring the magnetic flux density $B$ with a Hall probe, the magnetic force on a current‑carrying conductor can be quantified using $F = I L B$. The Hall effect provides a direct, reliable method for determining $B$, linking the electrical measurement (Hall voltage) to the mechanical effect (force).