Understand that a resistive force acting on an oscillating system causes damping, and explore the consequences for natural and forced oscillations.
For an undamped mass‑spring system the equation of motion is
$$m\ddot{x}+kx=0$$with solution $x(t)=A\cos(\omega_0 t+\phi)$ where $\omega_0=\sqrt{k/m}$.
A resistive force proportional to the velocity, $F_{\text{d}}=-b\dot{x}$, is common in real systems (air resistance, internal friction, electrical resistance in an RLC circuit). Adding this term gives the damped equation of motion
$$m\ddot{x}+b\dot{x}+kx=0$$where $b$ is the damping coefficient (units kg s⁻¹).
| Condition | Relation of $b$ to $2\sqrt{mk}$ | Behaviour |
|---|---|---|
| Underdamped | $b<2\sqrt{mk}$ | Oscillatory motion with exponentially decaying amplitude. |
| Critically damped | $b=2\sqrt{mk}$ | Returns to equilibrium as quickly as possible without overshoot. |
| Overdamped | $b>2\sqrt{mk}$ | Non‑oscillatory return to equilibrium, slower than critical. |
Define the damping ratio $\zeta =\dfrac{b}{2\sqrt{mk}}$ and the damped angular frequency $\omega_d = \omega_0\sqrt{1-\zeta^2}$.
The displacement is
$$x(t)=A e^{-\zeta\omega_0 t}\cos(\omega_d t+\phi)$$The amplitude decays as $A(t)=A e^{-\zeta\omega_0 t}$, illustrating how the resistive force reduces the oscillation amplitude over time.
The mechanical energy of the oscillator is
$$E(t)=\frac{1}{2}kA^2 e^{-2\zeta\omega_0 t}$$Because the damping force does negative work, energy is continuously removed from the system at a rate
$$\frac{dE}{dt} = -b\dot{x}^2$$When an external periodic driving force $F_{\text{ext}} = F_0\cos(\omega t)$ acts on the damped system, the equation becomes
$$m\ddot{x}+b\dot{x}+kx = F_0\cos(\omega t)$$The steady‑state (particular) solution is
$$x(t)=X(\omega)\cos(\omega t - \delta)$$with amplitude
$$X(\omega)=\frac{F_0/m}{\sqrt{(\omega_0^2-\omega^2)^2+(2\zeta\omega_0\omega)^2}}$$and phase lag
$$\tan\delta = \frac{2\zeta\omega_0\omega}{\omega_0^2-\omega^2}$$