Mass‑Defect, Nuclear Binding Energy and the Binding‑Energy‑per‑Nucleon Curve
Learning objectives
Define mass‑defect (Δm), binding energy (Eb) and binding‑energy‑per‑nucleon (Eb/A).
State and apply Einstein’s relation \(E=Δmc^{2}\) (including the conversion factor 1 u = 931.5 MeV c⁻²).
Write nuclides in the standard notation \({}^{A}_{Z}\!X\) and use it for simple decay equations.
Sketch the variation of \(E_{b}/A\) with nucleon number \(A\) and explain the shape of the curve.
Relate the curve to the energetics of nuclear fusion and fission.
Key definitions and notation
Mass‑defect (Δm)
\[
Δm = \bigl[Z\,m_{p}+N\,m_{n}\bigr] - m_{\text{nucleus}}
\]
where \(Z\) = number of protons, \(N=A-Z\) = number of neutrons, \(A\) = mass number.
The tabulated atomic mass already includes the electron masses, so the same value can be used directly for the nucleus.
Binding energy (Eb)**
\[
E_{b}=Δm\,c^{2}=Δm\times 931.5\;\text{MeV}
\]
(1 u = 931.5 MeV c⁻² is the energy equivalent of one atomic‑mass unit.)
Binding‑energy‑per‑nucleon (Eb/A) – the average energy that holds each nucleon in the nucleus; a convenient measure of nuclear stability.
\[
\Delta m = \bigl[ Z\,m_{p}+ (A-Z)\,m_{n}\bigr] - m_{\text{atom}}
\]
\[
E_{b}= \Delta m \times 931.5\;\text{MeV}
\qquad\qquad
\frac{E_{b}}{A}= \frac{E_{b}}{A}
\]
with \(m_{p}=1.007276\;\text{u}\) and \(m_{n}=1.008665\;\text{u}\).
Selected data (mass defect, binding energy and binding energy per nucleon)
Nuclide \({}^{A}_{Z}\!X\)
A
Δm (u)
Eb (MeV)
Eb/A (MeV)
\({}^{2}_{1}\!H\) (deuterium)
2
0.0022
2.05
1.02
\({}^{4}_{2}\!He\) (α‑particle)
4
0.0304
28.3
7.07
\({}^{12}_{6}\!C\)
12
0.0985
92.2
7.68
\({}^{16}_{8}\!O\)
16
0.1365
127.6
7.98
\({}^{56}_{26}\!Fe\)
56
0.4920
492.3
8.79
\({}^{62}_{28}\!Ni\)
62
0.5436
534.4
8.79 (≈8.794)
\({}^{238}_{92}\!U\)
238
1.7840
1664.0
7.00
Variation of binding‑energy‑per‑nucleon with nucleon number
The curve of \(E_{b}/A\) against \(A\) has a characteristic “mountain‑range” shape. The sketch below includes the key points required by the Cambridge 9702 syllabus.
Features of the curve
Rapid rise (A ≲ 20) – Adding a nucleon creates many new short‑range attractive pairs, while a large fraction of nucleons are still on the surface.
Broad maximum (A ≈ 56–62) – The most tightly bound nuclei are \({}^{56}_{26}\!Fe\) and \({}^{62}_{28}\!Ni\) (≈ 8.79 MeV per nucleon). Here the gain from extra nuclear attraction is almost cancelled by the growing Coulomb repulsion.
Gradual decline (A > 62) – Electrostatic repulsion between the increasing number of protons outweighs the additional nuclear force, so \(E_{b}/A\) falls to ≈ 7 MeV for the actinides.
Physical interpretation (why the curve has this shape)
Short‑range nuclear force – Each nucleon feels a strong attractive force only from its nearest neighbours. In very light nuclei many nucleons are on the surface and have fewer neighbours, giving a low \(E_{b}/A\).
Surface effect – The surface‑to‑volume ratio decreases as \(A\) grows, so the proportion of “unbound” surface nucleons falls, raising the average binding.
Electrostatic (Coulomb) repulsion – The repulsive energy grows roughly as \(Z^{2}\) and becomes dominant for heavy nuclei, pulling the curve down.
Stability – Nuclei near the peak are the most stable. Nuclei left of the peak can release energy by fusing (moving toward higher \(E_{b}/A\)); nuclei right of the peak can release energy by fissioning into fragments that lie nearer the peak.
\({}^{12}_{6}\!C\), \({}^{16}_{8}\!O\) (and heavier nuclei up to Fe‑group)
~7 MeV per nucleon added
Fission
\({}^{235}_{92}\!U\), \({}^{239}_{94}\!Pu\)
Two fragments with \(A\approx 90–150\) (e.g. \({}^{144}_{56}\!Ba\) + \({}^{89}_{36}\!Kr\))
~0.9 MeV per nucleon gained
Exam‑style tip
When asked to “sketch the variation of \(E_{b}/A\) with \(A\)”, remember the three labelled points:
Rapid rise up to \(A\approx20\)
Maximum at \(A\approx56\)–\(62\) (Fe‑56, Ni‑62)
Slow decline for \(A>62\) (≈ 7 MeV for uranium).
To compare fusion and fission, state which side of the curve the reactants lie on and which side the products lie on; the movement towards the peak indicates energy release.
Use the conversion \(1\;\text{u}=931.5\;\text{MeV}\) whenever you turn a mass defect into an energy value.
Summary
The binding‑energy‑per‑nucleon curve summarises the competition between the short‑range attractive nuclear force and the long‑range Coulomb repulsion. Its maximum near \({}^{62}_{28}\!Ni\) explains why both fusion (for light nuclei) and fission (for heavy nuclei) can release energy: the products occupy a higher point on the curve, i.e. they have a larger \(E_{b}/A\) and therefore a lower total mass‑energy.
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