By the end of this lesson you should be able to represent any vector as two perpendicular components.
Consider a vector $\vec{A}$ lying in the $xy$‑plane. It can be expressed as the sum of two perpendicular components along the $x$‑ and $y$‑axes:
$$\vec{A}=A_x\hat{i}+A_y\hat{j}$$where:
If the magnitude $A$ and the angle $\theta$ (measured from the positive $x$‑axis) are known, the components are obtained using trigonometry:
$$A_x = A\cos\theta$$ $$A_y = A\sin\theta$$The reverse relations give the magnitude and direction from the components:
$$A = \sqrt{A_x^{2}+A_y^{2}}$$ $$\theta = \tan^{-1}\!\left(\frac{A_y}{A_x}\right)$$Given a force $\vec{F}$ of magnitude $50\ \text{N}$ acting $30^{\circ}$ above the positive $x$‑axis, find its components.
| Vector Quantity | Symbol | Typical Units | Typical Components |
|---|---|---|---|
| Displacement | $\vec{s}$ | metre (m) | $s_x$, $s_y$ |
| Velocity | $\vec{v}$ | metre per second (m s⁻¹) | $v_x$, $v_y$ |
| Acceleration | $\vec{a}$ | metre per second squared (m s⁻²) | $a_x$, $a_y$ |
| Force | $\vec{F}$ | newton (N) | $F_x$, $F_y$ |
Any vector in a plane can be uniquely described by two perpendicular components. This representation simplifies vector addition, subtraction, and the application of Newton’s laws in two dimensions.