recall and use intensity = power/area and intensity ∝ (amplitude )2 for a progressive wave

Cambridge A-Level Physics 9702 – Progressive Waves

Progressive Waves

A progressive (or travelling) wave transports energy and momentum through a medium without permanent displacement of the medium itself. The wave front moves forward, and the disturbance at any point in the medium varies with time.

Suggested diagram: A sinusoidal progressive wave travelling to the right, showing successive crests and troughs.

Key Quantities

  • Amplitude ($A$): maximum displacement from equilibrium.
  • Wavelength ($\lambda$): distance between successive points in phase.
  • Frequency ($f$) and Angular frequency ($\omega = 2\pi f$).
  • Wave speed ($v$): $v = f\lambda$.
  • Power ($P$): rate at which energy is transmitted by the wave.
  • Intensity ($I$): power per unit area perpendicular to the direction of propagation.

Intensity Definition

The intensity of a wave is defined as

$$ I = \frac{P}{A_{\perp}} $$

where $P$ is the average power carried by the wave and $A_{\perp}$ is the area of a surface normal to the direction of propagation.

Relationship Between Intensity and Amplitude

For a harmonic progressive wave in a linear medium, the average power is proportional to the square of the amplitude. Consequently, the intensity is also proportional to $A^{2}$:

$$ I \propto A^{2} $$

Derivation (outline):

  1. The instantaneous energy density $u$ of a wave is the sum of kinetic and potential contributions: $$u = \frac{1}{2}\rho v^{2} + \frac{1}{2}kA^{2}\sin^{2}(kx-\omega t)$$ where $\rho$ is the medium density and $k$ the wave number.
  2. Both terms contain $A^{2}\sin^{2}(kx-\omega t)$. The time‑averaged energy density $\langle u\rangle$ therefore contains a factor $A^{2}$.
  3. Power is the product of energy density and wave speed: $P = \langle u\rangle v A_{\perp}$.
  4. Dividing by $A_{\perp}$ gives intensity $I = \langle u\rangle v$, which retains the $A^{2}$ dependence.

Practical Use of $I = P/A_{\perp}$ and $I \propto A^{2}$

These relationships allow you to:

  • Calculate the intensity of a sound or light beam when the power and cross‑sectional area are known.
  • Predict how the intensity changes when the amplitude of a wave is altered (e.g., turning up a speaker).
  • Compare intensities of different waves by examining their amplitudes.

Example Problem

Problem: A speaker emits a sinusoidal sound wave with an average power of $2.0\ \text{W}$ uniformly over a circular area of radius $0.10\ \text{m}$. Find the intensity at a distance where the wavefront is still approximately planar.

Solution:

  1. Calculate the area: $$A_{\perp} = \pi r^{2} = \pi (0.10\ \text{m})^{2} = 3.14\times10^{-2}\ \text{m}^{2}$$
  2. Use the intensity definition: $$I = \frac{P}{A_{\perp}} = \frac{2.0\ \text{W}}{3.14\times10^{-2}\ \text{m}^{2}} \approx 63.7\ \text{W m}^{-2}$$

Common Misconceptions

  • Intensity is not the same as amplitude. Intensity depends on the square of the amplitude, so halving the amplitude reduces intensity by a factor of four.
  • Intensity is not a vector. It is a scalar quantity representing power per unit area.
  • Area must be perpendicular to the direction of propagation. Using an oblique area will give an apparent intensity that is too low because the effective area is $A_{\perp}=A\cos\theta$.

Summary Table

Quantity Symbol Definition / Relation
Intensity $I$ $I = \dfrac{P}{A_{\perp}}$
Power $P$ Average rate of energy transport by the wave.
Amplitude $A$ Maximum displacement of the medium.
Intensity–Amplitude Relation $I \propto A^{2}$ For a harmonic progressive wave in a linear medium.
Wave Speed $v$ $v = f\lambda = \dfrac{\omega}{k}$

Key Take‑aways

  • Intensity quantifies how much power passes through a unit area perpendicular to the wave’s travel direction.
  • Because $I \propto A^{2}$, small changes in amplitude produce large changes in intensity.
  • When solving problems, always verify that the area used is the projected (perpendicular) area.