When a conductor carrying an electric current is placed in a magnetic field, the moving charge carriers experience the magnetic part of the Lorentz force. The resultant force on the whole conductor is given by
$$\mathbf{F}=I\,\mathbf{L}\times\mathbf{B}$$where
Consider a segment of wire of cross‑sectional area \(A\) containing charge carriers of charge \(q\) and number density \(n\). The drift velocity of the carriers is \(\mathbf{v}_d\). The magnetic force on a single carrier is
$$\mathbf{f}=q\,\mathbf{v}_d\times\mathbf{B}$$The total number of carriers in the segment of length \(L\) is \(N=nAL\). Summing the forces gives
$$\mathbf{F}=N\mathbf{f}=nAL\,q\,\mathbf{v}_d\times\mathbf{B}$$Since the current is \(I=nqA v_d\), we obtain the familiar result \(\mathbf{F}=I\mathbf{L}\times\mathbf{B}\).
A velocity selector allows only particles (or charge carriers) with a specific speed to pass undeflected. This is achieved by arranging uniform electric and magnetic fields perpendicular to each other and to the direction of particle motion.
For a particle of charge \(q\) moving with velocity \(\mathbf{v}\) through crossed fields \(\mathbf{E}\) and \(\mathbf{B}\) (with \(\mathbf{E}\perp\mathbf{B}\) and both perpendicular to \(\mathbf{v}\)), the net force is
$$\mathbf{F}=q\mathbf{E}+q\mathbf{v}\times\mathbf{B}$$To achieve zero net force (no deflection), the electric and magnetic forces must cancel:
$$q\mathbf{E}+q\mathbf{v}\times\mathbf{B}=0\quad\Longrightarrow\quad \mathbf{E}=-\mathbf{v}\times\mathbf{B}$$Since \(\mathbf{E}\) and \(\mathbf{B}\) are perpendicular, the magnitude condition simplifies to
$$E = vB\qquad\Longrightarrow\qquad v=\frac{E}{B}$$Only particles with speed \(v=E/B\) travel straight through the selector; faster particles are deflected upward by the magnetic force, slower particles downward by the electric force.
In a conductor the drift velocity of electrons is typically very small (≈ 10⁻⁴ m s⁻¹), so the magnetic force on the whole wire dominates. However, the same principle can be demonstrated using a beam of charged particles (e.g., electrons or ions) passing through a region where the conductor is placed. By adjusting \(\mathbf{E}\) and \(\mathbf{B}\) such that the selected velocity matches the drift velocity, the magnetic force on the moving carriers can be made to balance the electric force, effectively “nulling” the net force on the wire segment.
| Quantity | Expression | Units |
|---|---|---|
| Magnetic force on conductor | $\mathbf{F}=I\mathbf{L}\times\mathbf{B}$ | N |
| Electric force on charge | $\mathbf{F}=q\mathbf{E}$ | N |
| Velocity for zero net force | $v=\dfrac{E}{B}$ | m s⁻¹ |
| Drift velocity in a wire | $v_d=\dfrac{I}{nqA}$ | m s⁻¹ |