| Term | Definition (energy view) |
|---|---|
| Electromotive force (e.m.f.) ℰ | Work done **by the internal chemical, photovoltaic, etc. processes** of a source on a charge q while the charge moves **inside** the source from the negative to the positive terminal. \[ \boxed{\mathcal{E}= \frac{W_{\text{inside}}}{q}\quad\left[\text{J C}^{-1}= \text{V}\right]} \] |
| Potential difference (p.d.) V | Work done **by the external electric field** on a charge q as it moves **outside** the source between any two points of the circuit (e.g. across a resistor, lamp or the terminals under load). \[ \boxed{V= \frac{W_{\text{outside}}}{q}\quad\left[\text{J C}^{-1}= \text{V}\right]} \] |
When a current I flows, the source must supply energy both to the external circuit and to overcome the voltage drop across its internal resistance.
\[ \underbrace{V_{\text{terminal}}}_{\text{p.d. outside}} \;=\; \underbrace{\mathcal{E}}_{\text{e.m.f. inside}} \;-\; I\,r \]A real voltmeter has a finite internal resistance \(R_{\text{vm}}\). When it is connected across the source:
\[ I_{\text{vm}} = \frac{V_{\text{terminal}}}{R_{\text{vm}}} \]This small current adds to the circuit current, increasing the internal drop \(I_{\text{total}}r\) and causing the measured voltage to be slightly lower than the true terminal p.d. The effect is negligible only if \(R_{\text{vm}}\gg R_{\text{load}}\).
For a charge \(q\) that traverses the whole circuit:
| Aspect | e.m.f. ℰ | Potential Difference V |
|---|---|---|
| Physical meaning | Work done per coulomb **by internal processes** of the source (inside the source). | Work done per coulomb **by the external electric field** (outside the source). |
| Location in circuit | Across the ideal source; represented by the internal‑resistance model. | Across any component or the terminals when the source supplies current. |
| Sign convention | Positive from negative → positive terminal of the source. | Positive in the direction of conventional current (high → low potential). |
| Energy transfer per coulomb | Supplies energy \(W = q\mathcal{E}\). | Consumes (or stores) energy \(W = qV\) (e.g., heat in a resistor). |
| Measurement condition | Measured with a voltmeter **under open‑circuit** (no load current). | Measured with a voltmeter **while the circuit is operating** (load present). |
| Relation to internal resistance | Maximum possible voltage of the source. | Terminal voltage \(V = \mathcal{E} - Ir\). |
| Effect of voltmeter loading | Negligible if \(R_{\text{vm}}\gg r\); otherwise the reading is slightly low. | Same loading effect applies; must be considered when high accuracy is required. |
Uncertainty note (AO3): Record the voltmeter’s internal resistance and the tolerance of R; propagate these uncertainties to obtain an uncertainty for r.
Given a 12 V battery with internal resistance \(r = 0.5\;\Omega\) delivering a current \(I = 2\;\text{A}\) to an external resistor.
\[ \begin{aligned} \mathcal{E} &= 12\ \text{V} \\ V_{\text{terminal}} &= \mathcal{E} - I r = 12 - (2)(0.5) = 11\ \text{V} \\ \text{Energy supplied per coulomb} &= q\mathcal{E}=12\ \text{J C}^{-1} \\ \text{Energy delivered to external circuit per coulomb} &= qV_{\text{terminal}}=11\ \text{J C}^{-1} \\ \text{Energy lost in internal resistance per coulomb} &= qIr = 1\ \text{J C}^{-1}. \end{aligned} \]The 1 V (or 1 J C⁻¹) difference represents the heat generated inside the battery.
At any junction, the algebraic sum of currents entering equals the sum leaving.
\[ \sum I_{\text{in}} = \sum I_{\text{out}}. \]For any closed loop, the sum of the e.m.f.s and the algebraic sum of potential differences is zero. Using the energy view, each term represents work per coulomb.
\[ \sum \mathcal{E} - \sum V = 0. \]
Applying KCL at the node where the current splits:
\[ I = I_{1}+I_{2}. \]KVL around the left loop (ℰ → r → R₁ → R₃):
\[ \mathcal{E} - I r - I_{1}R_{1} - I_{3}R_{3}=0. \]KVL around the right loop (ℰ → r → R₂ → R₃):
\[ \mathcal{E} - I r - I_{2}R_{2} - I_{3}R_{3}=0. \]These equations, together with KCL, allow calculation of all branch currents, illustrating how the energy‑based voltages naturally satisfy Kirchhoff’s laws.
Two series resistors \(R_{1}\) and \(R_{2}\) across a source of e.m.f. ℰ share the total voltage in proportion to their resistances because the same current flows through each. The work per coulomb (voltage) across each resistor is:
\[ V_{R_{1}} = \mathcal{E}\,\frac{R_{1}}{R_{1}+R_{2}},\qquad V_{R_{2}} = \mathcal{E}\,\frac{R_{2}}{R_{1}+R_{2}}. \]
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