Define force as the rate of change of momentum and apply this definition to solve quantitative problems.
The linear momentum $\mathbf{p}$ of a particle of mass $m$ moving with velocity $\mathbf{v}$ is defined as
$$\mathbf{p}=m\mathbf{v}$$Momentum is a vector quantity; its direction is the same as the velocity vector.
Newton’s second law can be written most generally as
$$\mathbf{F} = \frac{d\mathbf{p}}{dt}$$where $\mathbf{F}$ is the net external force acting on the particle.
If the mass $m$ is constant, the derivative expands to
$$\mathbf{F}= \frac{d}{dt}(m\mathbf{v}) = m\frac{d\mathbf{v}}{dt}=m\mathbf{a}$$Thus the familiar form $\mathbf{F}=m\mathbf{a}$ is a special case of the more general momentum form.
When mass changes with time, the full derivative must be retained:
$$\mathbf{F}= \frac{d}{dt}(m\mathbf{v}) = m\frac{d\mathbf{v}}{dt}+\mathbf{v}\frac{dm}{dt}$$This expression is essential for analysing rockets and other systems where mass is ejected or accreted.
From the definition $\mathbf{F}=d\mathbf{p}/dt$, several useful results follow.
Integrating the definition over a finite time interval $[t_1,t_2]$ gives
$$\int_{t_1}^{t_2}\mathbf{F}\,dt = \mathbf{p}(t_2)-\mathbf{p}(t_1)=\Delta\mathbf{p}$$The left‑hand side is the impulse $\mathbf{J}$ delivered to the object:
$$\mathbf{J}= \int_{t_1}^{t_2}\mathbf{F}\,dt = \Delta\mathbf{p}$$Impulse has the same units as momentum (kg·m·s⁻¹) and provides a convenient way to relate forces that act over short time intervals (e.g., collisions).
If a constant force $\mathbf{F}$ acts for a time $\Delta t$, the change in momentum is simply
$$\Delta\mathbf{p}= \mathbf{F}\,\Delta t$$and the final velocity can be found from $\mathbf{p}=m\mathbf{v}$.
Problem: A 0.150 kg ball moving at $8.0\ \text{m s}^{-1}$ collides head‑on with a 0.250 kg ball at rest. The collision lasts $0.020\ \text{s}$ and the average force on each ball during the impact is $120\ \text{N}$. Find the final velocities of both balls assuming the collision is perfectly elastic.
| Quantity | Symbol | Definition / Equation | SI Unit |
|---|---|---|---|
| Momentum | $\mathbf{p}$ | $\mathbf{p}=m\mathbf{v}$ | kg·m·s⁻¹ |
| Force (general) | $\mathbf{F}$ | $\mathbf{F}=d\mathbf{p}/dt$ | N (kg·m·s⁻²) |
| Impulse | $\mathbf{J}$ | $\mathbf{J}= \int\mathbf{F}\,dt = \Delta\mathbf{p}$ | kg·m·s⁻¹ (same as momentum) |
| Constant‑force momentum change | $\Delta\mathbf{p}= \mathbf{F}\Delta t$ | ||
| Variable‑mass force | $\mathbf{F}=m\mathbf{a}+\mathbf{v}\,dm/dt$ |