$r$ is the distance from the centre of $M$ to the point of interest
Gravitational Potential Near Earth
For points close to the Earth's surface, the field can be approximated as uniform, giving
$$V = -g h + V_0$$
where $g = 9.81\ \text{m s}^{-2}$, $h$ is the height above a reference level, and $V_0$ is the potential at that reference level (often taken as zero at sea level).
Equipotential Surfaces
Because $V$ is a scalar, the direction of the gravitational field $\mathbf{g}$ is always perpendicular to equipotential surfaces:
$$\mathbf{g} = -abla V$$
This property is useful for visualising the field and for solving problems involving work.
Suggested diagram: Equipotential surfaces around a spherical mass with field lines perpendicular to the surfaces.
Relation to Temperature
When gravitational potential energy is converted into other forms, the temperature of a system can change. Two common contexts are:
Atmospheric heating: As air descends in the Earth's gravitational field, its potential energy decreases and is converted into kinetic energy, which can increase temperature (adiabatic heating).
Accretion processes: In astrophysics, material falling into a deep gravitational potential well releases energy that heats the accretion disc, raising its temperature.
Worked Example
Calculate the gravitational potential at a distance of $2.0 \times 10^{7}\ \text{m}$ from the centre of the Earth. Use $M_{\earth}=5.97\times10^{24}\ \text{kg}$.
Interpretation: A 1‑kg mass at this altitude has $1.99\times10^{7}\ \text{J}$ less potential energy than at infinity.
Common Mistakes
Confusing gravitational potential ($V$) with gravitational field strength ($g$). $V$ is energy per unit mass (J kg⁻¹); $g$ is force per unit mass (m s⁻²).
Neglecting the negative sign in $V = -GM/r$, which indicates that work must be done against the field to increase $r$.
Assuming the uniform field approximation ($V = -gh$) is valid far from Earth’s surface.
Summary Table
Quantity
Symbol
Formula
Units
Gravitational constant
$G$
$6.674 \times 10^{-11}$
N m² kg⁻²
Gravitational potential energy
$U$
$-\dfrac{GMm}{r}$
J
Gravitational potential
$V$
$-\dfrac{GM}{r}$
J kg⁻¹
Gravitational field strength (near Earth)
$g$
$9.81$ (approx.)
m s⁻²
Further Practice Questions
Derive the expression for the change in gravitational potential when moving from height $h_1$ to $h_2$ above the Earth’s surface, assuming $h \ll R_{\earth}$.
A 2 kg mass falls from a height of 500 m. Calculate the increase in its temperature if all the loss of gravitational potential energy is converted to internal energy. (Specific heat capacity of the material = $900\ \text{J kg}^{-1}\text{K}^{-1}$.)
Explain why equipotential surfaces around a non‑spherical planet are not perfect spheres.
Key Take‑aways
Gravitational potential is a scalar field representing potential energy per unit mass.
It is negative for attractive forces and becomes less negative as distance increases.
Energy released from changes in gravitational potential can raise the temperature of a system.
Equipotential surfaces provide a useful visual tool for understanding the direction of the gravitational field.