Capacitance

Capacitance

1. Definition and Fundamental Relation

  • Capacitance is the ability of a system to store electric charge per unit potential difference.
  • For any capacitor the capacitance C is defined by $$C=\frac{Q}{V}$$ where Q is the magnitude of charge on each plate (or conductor) and V is the potential difference between the conductors.

2. Symbol, SI Unit and Common Multiples

  • Symbol: C
  • SI unit: farad (F) \(1\;\text{F}=1\;\text{C V}^{-1}\)
  • Common sub‑multiples (used in examinations):
    • microfarad (µF) \(1\;\mu\text{F}=10^{-6}\;\text{F}\)
    • nanofarad (nF) \(1\;\text{nF}=10^{-9}\;\text{F}\)
    • picofarad (pF) \(1\;\text{pF}=10^{-12}\;\text{F}\)

3. Capacitance of Simple Conductors

3.1 Parallel‑plate capacitor

For an ideal parallel‑plate arrangement the capacitance is

$$C=\frac{\varepsilon A}{d}$$
  • \(A\) – plate area (m²)
  • \(d\) – separation between the plates (m)
  • \(\varepsilon\) – absolute permittivity of the material between the plates.
Effect of a dielectric

If a dielectric of relative permittivity \(\varepsilon_{r}\) fills the space,

$$\varepsilon=\varepsilon_{0}\varepsilon_{r},\qquad \varepsilon_{0}=8.85\times10^{-12}\;\text{F m}^{-1}$$

The capacitance is increased by the factor \(\varepsilon_{r}\).

Quick derivation (AO2)

The electric field between the plates is \(E=V/d\). Surface charge density \(\sigma = Q/A\). From Gauss’s law \(E=\sigma/\varepsilon\) ⇒ \(\sigma=\varepsilon V/d\). Substituting \(\sigma=Q/A\) gives \(Q=(\varepsilon A/d)V\) ⇒ \(C=Q/V=\varepsilon A/d\).

3.2 Isolated spherical conductor

An isolated conducting sphere of radius \(r\) behaves as a single‑plate capacitor whose other “plate’’ is at infinity. Its capacitance is

$$C_{\text{sphere}}=4\pi\varepsilon_{0}r$$
  • Only the radius matters – the larger the sphere, the larger the capacitance.
  • Useful for AO1 questions that ask for the capacitance of a single conductor (e.g. a metal ball of radius 5 cm has \(C\approx5.6\;\text{pF}\)).

4. Combination of Capacitors

4.1 Series connection

  • Same charge \(Q\) flows through each capacitor.
  • Total voltage is the sum of individual voltages: $$V_{\text{tot}}=V_{1}+V_{2}+\dots+V_{n}$$
  • Using \(V_i=Q/C_i\) leads to $$\frac{1}{C_{\text{eq}}}= \frac{1}{C_{1}}+\frac{1}{C_{2}}+\dots+\frac{1}{C_{n}}$$

4.2 Parallel connection

  • All capacitors experience the same voltage \(V\).
  • Total charge is the sum of the individual charges: $$Q_{\text{tot}}=Q_{1}+Q_{2}+\dots+Q_{n}$$
  • Since \(Q_i=C_iV\), the equivalent capacitance is $$C_{\text{eq}}=C_{1}+C_{2}+\dots+C_{n}$$

4.3 Example – Series‑parallel network

  1. Two capacitors, \(C_{1}=4.0\;\mu\text{F}\) and \(C_{2}=6.0\;\mu\text{F}\), are in series; the combination is placed in parallel with \(C_{3}=3.0\;\mu\text{F}\). The network is connected to a 12 V battery.
  2. Find the equivalent capacitance, the charge on each capacitor, and the total energy stored.

Solution

  • Series part: $$\frac{1}{C_{s}}=\frac{1}{4.0\;\mu\text{F}}+\frac{1}{6.0\;\mu\text{F}}=\frac{5}{12\;\mu\text{F}}\;\Rightarrow\;C_{s}=2.4\;\mu\text{F}$$
  • Parallel addition: $$C_{\text{eq}}=C_{s}+C_{3}=2.4\;\mu\text{F}+3.0\;\mu\text{F}=5.4\;\mu\text{F}$$
  • Charge (same for the series pair): $$Q=C_{\text{eq}}V=5.4\;\mu\text{F}\times12\;\text{V}=64.8\;\mu\text{C}$$
  • Energy stored: $$U=\tfrac12 C_{\text{eq}}V^{2}= \tfrac12(5.4\;\mu\text{F})(12\;\text{V})^{2}=3.89\times10^{-4}\;\text{J}=388.8\;\mu\text{J}$$

4.4 Capacitors as a potential divider (Paper 2/4 topic)

For two capacitors in series, the voltage across each is proportional to the *other* capacitance:

$$V_{1}=V_{\text{tot}}\frac{C_{2}}{C_{1}+C_{2}},\qquad V_{2}=V_{\text{tot}}\frac{C_{1}}{C_{1}+C_{2}}$$

This is frequently used to obtain a required fraction of a supply voltage without resistors.

5. Energy Stored in a Capacitor

Starting from the definition \(U=\displaystyle\int_{0}^{Q}V\,\mathrm{d}Q\) and using \(V=Q/C\):

$$U=\frac12\frac{Q^{2}}{C}$$

Because \(Q=CV\), the same expression can be written in two equivalent forms:

$$U=\frac12CV^{2}= \frac12QV$$
  • Energy varies with the square of the voltage – doubling \(V\) quadruples the stored energy.
  • The three forms are useful in different exam questions (e.g. when \(Q\) is known, use \(U=\tfrac12Q^{2}/C\)).

6. Charging and Discharging – RC Time Constant

6.1 Definition

When a capacitor of capacitance \(C\) is connected to a resistor \(R\), the circuit has a time constant

$$\tau = RC$$

After a time \(\tau\) the voltage (and charge) has fallen to \(\displaystyle\frac{1}{e}\approx36.8\%\) of its initial value.

6.2 Exponential decay (AO2)

Applying Kirchhoff’s loop rule to a discharging circuit (\(V_{C}+V_{R}=0\)) gives

$$\frac{Q}{C}+R\frac{\mathrm{d}Q}{\mathrm{d}t}=0$$

Integrating,

$$Q(t)=Q_{0}\,e^{-t/RC},\qquad V(t)=V_{0}\,e^{-t/RC}$$

where \(Q_{0}=CV_{0}\) is the initial charge.

6.3 Example – Discharge calculation

A 10 µF capacitor is charged to 15 V and then discharged through a 200 kΩ resistor. Find the voltage after 0.5 s.

  • \(\tau = RC = (2.0\times10^{5}\;\Omega)(1.0\times10^{-5}\;\text{F}) = 2\;\text{s}\)
  • \(V(t)=V_{0}e^{-t/\tau}=15\,e^{-0.5/2}=15\,e^{-0.25}\approx15\times0.779=11.7\;\text{V}\)

7. Common Types of Capacitors

Type Dielectric Material Typical Applications Capacitance Range
Ceramic Metal‑oxide ceramic High‑frequency circuits, decoupling pF – µF
Electrolytic Aluminium oxide (wet) or tantalum Power‑supply filtering, bulk storage µF – mF
Film Polypropylene, polyester Audio, precision timing, low‑loss filters nF – µF
Mica Natural mica RF circuits, temperature‑stable capacitance pF – nF

8. Practical Considerations

  • Voltage rating: Never exceed the specified maximum; breakdown destroys the component.
  • Leakage current: Real capacitors slowly discharge even when isolated – important for timing circuits.
  • Polarity: Electrolytic and tantalum capacitors are polarized; reversing them causes failure.
  • Temperature coefficient: Dielectric constant may vary with temperature; choose a type with suitable stability for precision work.
  • Physical size vs. capacitance: Higher capacitance generally requires larger plate area or higher‑\(\varepsilon_{r}\) dielectrics.

9. Summary of Key Points (AO1)

  • Capacitance quantifies how much charge a system can store per volt: \(C=Q/V\).
  • For a parallel‑plate capacitor \(C=\varepsilon A/d\); inserting a dielectric multiplies \(C\) by \(\varepsilon_{r}\).
  • An isolated spherical conductor has \(C=4\pi\varepsilon_{0}r\).
  • Series combination: \(\displaystyle\frac{1}{C_{\text{eq}}}= \sum\frac{1}{C_i}\) – the smallest capacitor dominates the total.
  • Parallel combination: \(C_{\text{eq}}=\sum C_i\) – capacitances add directly.
  • Energy stored: \(U=\tfrac12CV^{2}= \tfrac12Q^{2}/C= \tfrac12QV\); it grows with the square of the voltage.
  • RC time constant \(\tau = RC\) governs charging and discharging; voltage decays exponentially as \(V=V_{0}e^{-t/\tau}\).
  • Series capacitors act as a potential divider: \(V_{1}=V_{\text{tot}}C_{2}/(C_{1}+C_{2})\).
  • Always respect voltage rating, polarity, leakage, and temperature specifications when selecting a capacitor for a circuit.

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