1 Motion, Forces & Energy (Core)
1.1 Physical Quantities, Units & Symbols
| Quantity | Symbol | SI Unit | Typical IGCSE Range |
| Distance / displacement | s, Δs | metre (m) | 0.01 m – 200 m |
| Time | t, Δt | second (s) | 0.1 s – 600 s |
| Speed / velocity | v, u, v_f | metre per second (m s⁻¹) | 0.5 m s⁻¹ – 30 m s⁻¹ |
| Acceleration | a | metre per second squared (m s⁻²) | 0.1 m s⁻² – 10 m s⁻² |
| Mass | m | kilogram (kg) | 0.01 kg – 100 kg |
| Force | F | newton (N) | 0.5 N – 200 N |
| Momentum | p | kilogram metre per second (kg m s⁻¹) | 0.1 kg m s⁻¹ – 500 kg m s⁻¹ |
| Kinetic energy | E_k | joule (J) | 0.1 J – 10⁴ J |
| Work / energy | W, E | joule (J) | 1 J – 10⁵ J |
| Power | P | watt (W) | 1 W – 5000 W |
| Pressure | p | pascal (Pa) | 10³ Pa – 10⁶ Pa |
1.2 Vectors & Resultants
- Vectors have magnitude and direction; scalars have magnitude only.
- Resultant of two perpendicular vectors A and B:
\[
R=\sqrt{A^{2}+B^{2}}
\]
- Graphical method – tip‑to‑tail (parallelogram) construction.
1.3 Distance‑time & Speed‑time Graphs
- Distance‑time (s‑t): slope = speed; area = not used.
- Speed‑time (v‑t): slope = acceleration; area = distance travelled.
- Horizontal line → constant speed; straight line through origin → constant acceleration.
1.4 Equations of Motion (constant acceleration)
\[
\begin{aligned}
v &= u + a t \\
s &= u t + \tfrac12 a t^{2} \\
v^{2} &= u^{2} + 2 a s
\end{aligned}
\]
Where u = initial speed, v = final speed, s = displacement.
1.5 Newton’s Laws of Motion
- Law of Inertia – an object remains at rest or in uniform motion unless acted on by a net force.
- Second law – F = m a. Units: N = kg·m s⁻².
- Third law – For every action there is an equal and opposite reaction.
1.6 Momentum & Impulse (Supplement)
Momentum:
\[
p = m v
\]
Impulse (change in momentum):
\[
J = F\Delta t = \Delta p = m\Delta v
\]
Relation to kinetic energy (useful when only momentum is known):
\[
E_k = \frac{p^{2}}{2m}
\]
1.7 Kinetic Energy
Recall the kinetic‑energy equation:
\[
E_k = \frac12\,m\,v^{2}
\]
Derivation (work‑energy theorem)
\[
W = \int_{0}^{s}F\,\mathrm{d}s = \int_{0}^{v} m a\,\frac{v}{a}\,\mathrm{d}v
= \int_{0}^{v} m v\,\mathrm{d}v = \tfrac12 m v^{2}
\]
Thus the net work done on an object equals its change in kinetic energy.
Worked Example
Problem: A 0.15 kg tennis ball leaves the racket at 35 m s⁻¹. Find its kinetic energy.
\[
E_k = \tfrac12 \times 0.15 \times (35)^{2}
= 0.075 \times 1225
= 91.9\ \text{J} \approx 92\ \text{J}
\]
Common Mistakes
- Forgetting to square the speed.
- Using grams instead of kilograms.
- Omitting the factor ½.
- Confusing kinetic energy (J) with momentum (kg m s⁻¹).
1.8 Work, Energy Transfer & Power
- Work (constant force): \(W = F s\) (J)
- Work‑energy theorem: \(W_{\text{net}} = \Delta E_k\)
- Power: \(P = \dfrac{W}{t} = \dfrac{\Delta E}{t}\) (W)
Worked Example – Pulling a Block
A 5 kg block is pulled across a frictionless floor by a 20 N force over 3 m, starting from rest. Find its final speed.
\[
W = Fs = 20 \times 3 = 60\ \text{J}
\]
\[
\Delta E_k = 60 = \tfrac12 \times 5 \times v^{2}
\;\Rightarrow\; v^{2}=24\;\Rightarrow\; v = 4.9\ \text{m s}^{-1}
\]
1.9 Pressure
Pressure is force per unit area:
\[
p = \frac{F}{A}\qquad\text{(Pa)}
\]
Example
A rider exerts 800 N on a tyre with contact area 0.02 m².
\[
p = \frac{800}{0.02}=4.0\times10^{4}\ \text{Pa}=0.4\ \text{bar}
\]
1.10 Energy Stores & Conversions
| Store | Symbol | Formula (where applicable) | Typical Example |
| Kinetic | E_k | \(\tfrac12 m v^{2}\) | Moving car |
| Gravitational‑potential | E_g | \(m g h\) | Water behind a dam |
| Elastic | E_e | \(\tfrac12 k x^{2}\) | Stretched spring |
| Thermal (internal) | E_{th} | \(m c \Delta\theta\) | Hot water |
| Chemical | E_c | — | Battery, food |
| Electrostatic | E_{es} | \(\tfrac12 C V^{2}\) | Charged capacitor |
| Nuclear | E_n | — | Radioactive decay |
Energy is conserved; it can be transferred between stores (e.g., a falling object converts E_g to E_k).
2 Thermal Physics (Core)
2.1 Particle Model of Matter
- Solids: particles tightly packed, vibrate about fixed positions.
- Liquids: particles close but can move past one another.
- Gases: particles far apart, move freely.
2.2 Temperature & Temperature Scales
- Thermometers measure temperature (θ).
- Conversion: \(\displaystyle T\ (\text{K}) = \theta\ (\!^\circ\text{C}) + 273\).
2.3 Specific Heat Capacity
Energy required to raise the temperature of 1 kg of a substance by 1 K:
\[
Q = m c \Delta\theta
\]
where \(Q\) is heat energy (J), \(c\) is specific heat capacity (J kg⁻¹ K⁻¹).
Worked Example
How much energy is needed to heat 0.5 kg of aluminium (c = 900 J kg⁻¹ K⁻¹) from 20 °C to 80 °C?
\[
Q = 0.5 \times 900 \times (80-20) = 0.5 \times 900 \times 60 = 27\,000\ \text{J}
\]
2.4 Latent Heat (Phase Change)
\[
Q = m L
\]
- L_f – latent heat of fusion (solid↔liquid).
- L_v – latent heat of vaporisation (liquid↔gas).
Example
Calculate the energy required to melt 0.2 kg of ice (L_f = 3.3 × 10⁵ J kg⁻¹).
\[
Q = 0.2 \times 3.3\times10^{5}=6.6\times10^{4}\ \text{J}
\]
2.5 Thermal Expansion
Linear expansion: \(\displaystyle \Delta L = \alpha L_0 \Delta\theta\) (α = coefficient of linear expansion).
Area expansion: \(\displaystyle \Delta A = 2\alpha A_0 \Delta\theta\).
2.6 Heat Transfer Methods
- Conduction: direct particle collisions; rate \( \dot Q = \frac{kA}{d}\Delta\theta\).
- Convection: bulk movement of fluid; described qualitatively.
- Radiation: electromagnetic waves; power \(P = \varepsilon\sigma A T^{4}\).
3 Waves (Core)
3.1 Wave Terminology
- Wave: disturbance that transfers energy without permanent displacement of matter.
- Amplitude (A), wavelength (λ), frequency (f), period (T), speed (v).
Fundamental relation:
\[
v = f\lambda = \frac{\lambda}{T}
\]
3.2 Reflection & Refraction
- Reflection: angle of incidence = angle of reflection.
- Refraction: change of direction when wave passes into a medium with different speed; Snell’s law \(\displaystyle n_1\sin\theta_1 = n_2\sin\theta_2\).
3.3 Diffraction
Significant when the obstacle size is comparable to the wavelength. Demonstrated with water waves or sound through a doorway.
3.4 Light – Mirrors & Lenses
- Plane mirror: image distance = object distance, laterally inverted.
- Concave mirror: focal length f, mirror equation \(\displaystyle \frac{1}{u}+\frac{1}{v}= \frac{1}{f}\).
- Convex lens: real image (if object beyond f) or virtual image (if within f); same lens formula.
3.5 Sound
- Longitudinal wave; speed in air ≈ 340 m s⁻¹ (depends on temperature).
- Pitch ∝ frequency; loudness ∝ amplitude.
3.6 Electromagnetic Spectrum (Supplement)
From low to high frequency: radio → microwave → infrared → visible → ultraviolet → X‑ray → gamma‑ray.
4 Electricity & Magnetism (Core)
4.1 Charge, Current & Potential Difference
- Charge (Q) measured in coulombs (C). 1 C = 6.25 × 10¹⁸ e⁻.
- Current (I) = charge flow per unit time: \(I = \dfrac{\Delta Q}{\Delta t}\) (A).
- Potential difference (V) = energy per unit charge: \(V = \dfrac{W}{Q}\) (V).
4.2 Resistance & Ohm’s Law
\[
V = I R
\]
Resistivity: \(R = \rho \dfrac{L}{A}\) (Ω), where ρ is material resistivity.
4.3 Series & Parallel Circuits
- Series: \(R_{\text{eq}} = R_1+R_2+\dots\); same current, voltages add.
- Parallel: \(\displaystyle \frac{1}{R_{\text{eq}}}= \frac{1}{R_1}+ \frac{1}{R_2}+ \dots\); same voltage, currents add.
4.4 Electrical Power & Energy
\[
P = VI = I^{2}R = \frac{V^{2}}{R}
\qquad
E = Pt
\]
Worked Example – Electric Kettle
Power = 2 kW, time = 3 min.
\[
E = P t = 2000 \times 180 = 3.6\times10^{5}\ \text{J}
\]
4.5 Magnetic Fields
- Field lines emerge from north pole, enter south pole.
- Force on a moving charge: \(\displaystyle \mathbf{F}=q\mathbf{v}\times\mathbf{B}\).
- Force on a current‑carrying conductor: \(\displaystyle F = B I L \sin\theta\).
4.6 Electromagnetic Induction (Supplement)
Changing magnetic flux through a coil induces an emf (Faraday’s law):
\[
\mathcal{E} = -N\frac{\Delta \Phi}{\Delta t}
\]
where \(\Phi = B A\) is magnetic flux.
5 Nuclear Physics (Core)
5.1 Radioactivity
- Alpha (α) particles: +2 e, heavy, low penetration.
- Beta (β) particles: electrons, moderate penetration.
- Gamma (γ) rays: high‑energy photons, highly penetrating.
5.2 Half‑Life
\[
N = N_0\left(\frac{1}{2}\right)^{t/t_{1/2}}
\]
Useful for dating and calculating activity.
5.3 Nuclear Reactions & Energy Release
- Fission: heavy nucleus → lighter fragments + energy.
- Fusion: light nuclei combine → heavier nucleus + energy.
Energy released per nucleon ≈ 8 MeV, far greater than chemical reactions.
6 Space Physics (Core)
6.1 Universal Gravitation
\[
F = G\frac{m_1 m_2}{r^{2}}
\qquad
g = G\frac{M_{\earth}}{R_{\earth}^{2}} \approx 9.8\ \text{m s}^{-2}
\]
6.2 Satellite Motion & Orbital Speed
\[
\frac{mv^{2}}{r} = G\frac{M_{\earth}m}{r^{2}}
\;\Rightarrow\;
v = \sqrt{\frac{G M_{\earth}}{r}}
\]
6.3 Escape Velocity
\[
v_{\text{esc}} = \sqrt{\frac{2 G M_{\earth}}{R_{\earth}}}\approx 11.2\ \text{km s}^{-1}
\]
7 Practical Skills (Across All Topics)
7.1 Experimental Design
- Identify variables: independent, dependent, controlled.
- Plan a method that isolates the effect of the independent variable.
- Include safety considerations (e.g., PPE, electrical hazards).
7.2 Uncertainty & Error Analysis
- Absolute uncertainty: ± value (e.g., ±0.01 m).
- Relative (fractional) uncertainty: \(\displaystyle \frac{\Delta x}{x}\).
- Propagation for multiplication/division: add relative uncertainties.
7.3 Graphical Interpretation
- Gradient = \(\Delta y/\Delta x\) → physical quantity (e.g., speed, resistance).
- Area under a curve → accumulated quantity (e.g., work, impulse).
- Best‑fit straight line → use two points or linear regression.
7.4 Common Laboratory Techniques
- Using stop‑watches and meter‑sticks – estimate reaction time and reading errors.
- Voltage and current measurement – correct use of voltmeter (parallel) and ammeter (series).
- Measuring mass – use of balance, tare function, and avoiding static charge.
Practice Questions (All Core Codes)
- (1.7.1 Core) A 2 kg cart moves at 4 m s⁻¹. What is its kinetic energy?
- (1.7.1 Core) A cyclist of mass 70 kg (including bike) travels at 6 m s⁻¹. Calculate the kinetic energy.
- (1.7.1 Core) If a ball’s kinetic energy is 20 J and its mass is 0.2 kg, what is its speed?
- (1.7.2 Supplement) Two objects have the same kinetic energy. One has a mass of 0.5 kg; the other has a mass of 2 kg. Which one is moving faster, and by what factor?
- (1.2 Core) A 3 kg crate is pulled by a constant 15 N force over 5 m from rest. Find its final speed.
- (1.3 Core) A 1500 W hair‑dryer runs for 5 minutes. How much energy does it use?
- (1.4 Core) A force of 250 N is applied to a piston of area 0.005 m². Calculate the pressure exerted.
- (2.3 Core) How much energy is required to heat 0.8 kg of water from 20 °C to 80 °C? (c_water = 4180 J kg⁻¹ K⁻¹)
- (2.4 Core) 0.1 kg of ice at 0 °C melts completely. Find the heat absorbed. (L_f = 3.3 × 10⁵ J kg⁻¹)
- (3.1 Core) A wave has a frequency of 50 Hz and a wavelength of 0.6 m. Calculate its speed.
- (3.4 Core) An object is placed 0.15 m in front of a concave mirror with focal length 0.10 m. Determine the image distance and nature of the image.
- (4.2 Core) A 10 Ω resistor is connected to a 12 V supply. Find the current and power dissipated.
- (4.5 Core) A straight conductor 0.30 m long carries 5 A perpendicular to a magnetic field of 0.2 T. Find the magnetic force on the conductor.
- (5.2 Core) A sample contains 8 × 10⁶ radioactive nuclei. Its half‑life is 2 h. How many nuclei remain after 6 h?
- (6.2 Core) Calculate the orbital speed of a satellite 400 km above Earth’s surface. (R_earth = 6.37 × 10⁶ m, M_earth = 5.97 × 10²⁴ kg)
Answers
- \(E_k = \tfrac12 \times 2 \times 4^{2}=16\ \text{J}\)
- \(E_k = \tfrac12 \times 70 \times 6^{2}=1260\ \text{J}\)
- \(v = \sqrt{\dfrac{2E_k}{m}} = \sqrt{\dfrac{2\times20}{0.2}} = \sqrt{200}\approx 14.1\ \text{m s}^{-1}\)
- For equal \(E_k\): \(\dfrac{v_{0.5}}{v_{2}} = \sqrt{\dfrac{2}{0.5}} = 2\).
The 0.5 kg object moves twice as fast.
- \(W = Fs = 15 \times 5 = 75\ \text{J}\)
\(\tfrac12 \times 3 \times v^{2}=75 \Rightarrow v^{2}=50 \Rightarrow v\approx7.1\ \text{m s}^{-1}\)
- \(P=1500\ \text{W},\; t=5\ \text{min}=300\ \text{s}\)
\(E = Pt = 1500 \times 300 = 4.5\times10^{5}\ \text{J}\)
- \(p = \dfrac{250}{0.005}=5.0\times10^{4}\ \text{Pa}=0.5\ \text{bar}\)
- \(Q = mc\Delta\theta = 0.8 \times 4180 \times (80-20)=2.0\times10^{6}\ \text{J}\)
- \(Q = m L_f = 0.1 \times 3.3\times10^{5}=3.3\times10^{4}\ \text{J}\)
- \(v = f\lambda = 50 \times 0.6 = 30\ \text{m s}^{-1}\)
- Mirror formula: \(\frac{1}{u}+\frac{1}{v}= \frac{1}{f}\) with \(u = -0.15\ \text{m}, f = -0.10\ \text{m}\).
\(\frac{1}{v}= \frac{1}{-0.10} - \frac{1}{-0.15}= -10 + 6.\overline{6}= -3.\overline{3}\) → \(v = -0.30\ \text{m}\).
Image is real, inverted, and twice the size of the object.
- \(I = V/R = 12/10 = 1.2\ \text{A}\)
\(P = VI = 12 \times 1.2 = 14.4\ \text{W}\)
- \(F = B I L = 0.2 \times 5 \times 0.30 = 0.30\ \text{N}\)
- \(N = 8\times10^{6}\left(\frac12\right)^{6/2}=8\times10^{6}\left(\frac12\right)^{3}=8\times10^{6}\times\frac{1}{8}=1\times10^{6}\)
- \(r = R_{\earth}+400\,000 = 6.77\times10^{6}\ \text{m}\)
\(v = \sqrt{\frac{GM_{\earth}}{r}} = \sqrt{\frac{6.67\times10^{-11}\times5.97\times10^{24}}{6.77\times10^{6}}}\approx 7.7\times10^{3}\ \text{m s}^{-1}\)
Suggested Diagrams
- Vector addition (tip‑to‑tail) for two perpendicular forces.
- Distance‑time and speed‑time graphs illustrating constant speed and constant acceleration.
- Block being pushed: force F, displacement s, work W = Fs, resulting kinetic‑energy increase.
- Energy‑store Sankey diagram showing conversion from gravitational‑potential to kinetic to thermal.
- Ray diagram for a concave mirror (object beyond f, real inverted image).
- Circuit schematic showing series and parallel resistor combinations with a voltmeter and ammeter.
- Diagram of a satellite in circular orbit illustrating radius r and orbital speed v.