Describe the use of transformers in high‑voltage transmission of electricity.
1. Why Transmit at High Voltage?
Power loss in a line is \(P_{\text{loss}} = I^{2}R\) (I = current, R = resistance).
For a required transmitted power \(P\), the current is \(I = \dfrac{P}{V}\).
Increasing the transmission voltage V therefore reduces the current and the I²R losses.
Lower current also means thinner, cheaper conductors can be used for the same power rating.
2. Construction of a Transformer
Primary winding – coil connected to the source of alternating current.
Secondary winding – coil that delivers the transformed voltage to the load.
Core – closed magnetic circuit, normally laminated iron sheets to minimise eddy‑current loss.
3. Principle of Operation
When an alternating current flows in the primary winding it creates a time‑varying magnetic flux \(\Phi\) in the core. This changing flux links the secondary winding and induces an emf according to Faraday’s law. The induced emf is proportional to the rate of change of flux and to the number of turns in the winding.
4. Key Terminology
Step‑up transformer – secondary has more turns than the primary (\(N_{s}>N_{p}\)); secondary voltage is higher.
Step‑down transformer – secondary has fewer turns than the primary (\(N_{s}
Turns ratio – \(\dfrac{N_{p}}{N_{s}}\) where \(N_{p}\) and \(N_{s}\) are the numbers of turns in the primary and secondary.
Raise the voltage for long‑distance transmission, reducing current and losses.
10 : 1 (e.g., 20 kV → 400 kV)
Step‑down
Lower the voltage for safe distribution to homes, commercial and industrial users.
1 : 10 (e.g., 400 kV → 40 kV)
7. Example Calculation
Given: Power‑station output = 500 MW at 20 kV. A step‑up transformer raises the voltage to 400 kV for transmission. Line resistance = 0.05 Ω.
Current at generating voltage
\[
I_{\text{low}} = \frac{P}{V_{\text{low}}}
= \frac{500\times10^{6}\,\text{W}}{20\times10^{3}\,\text{V}}
= 25\,000\ \text{A}
\]
Current after stepping up
\[
I_{\text{high}} = \frac{P}{V_{\text{high}}}
= \frac{500\times10^{6}}{400\times10^{3}}
= 1\,250\ \text{A}
\]
The loss is reduced by a factor of \(\dfrac{31.25}{0.078}\approx 400\), illustrating the economic advantage of high‑voltage transmission.
8. Real‑World Efficiency and Design Considerations
Losses
Copper loss – I²R heating in the windings.
Core loss – hysteresis and eddy‑current losses in the laminated iron.
Large power‑transmission transformers typically achieve **98–99 %** efficiency.
Cooling – oil‑filled or forced‑air systems remove heat from windings and core.
Voltage regulation – on‑load tap changers adjust the turns ratio to keep the secondary voltage constant despite load variations.
9. Safety and Environmental Aspects
All high‑voltage equipment is insulated, earthed and clearly sign‑posted to protect personnel.
Transformers are housed in secure substations with barriers and warning signs.
Oil‑filled units require spill containment and fire‑suppression measures.
Acoustic enclosures or silencers reduce noise from cooling fans and magnetostriction humming.
10. Summary
Transformers make long‑distance electricity transmission economical. By stepping up the voltage, they reduce the current and the associated I²R losses, allowing thinner conductors and lower operating costs. After transmission, step‑down transformers bring the voltage to safe levels for distribution to homes and industry. Understanding the construction, terminology, ideal equations, efficiency factors and safety measures enables students to answer IGCSE questions on high‑voltage power transmission confidently.
Suggested diagram: (a) Power‑station step‑up transformer, (b) high‑voltage transmission lines, (c) substation step‑down transformer supplying a distribution network.
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