State that the main ore of aluminium is bauxite and that aluminium is extracted from this ore by electrolysis (the Hall–Héroult process). Explain why aluminium cannot be reduced by carbon using the reactivity‑series argument.
Al(OH)₃γ‑AlO(OH)α‑AlO(OH)Fe₂O₃, TiO₂, silica are present and must be removed before aluminium can be produced.NaOH → soluble sodium aluminate.
Al₂O₃·xH₂O + 2 NaOH → 2 NaAlO₂ + (x+1) H₂O
NaAlO₂ + 2 H₂O → Al(OH)₃↓ + NaOH
Al₂O₃).
2 Al(OH)₃ → Al₂O₃ + 3 H₂O
Al > C (more reactive).Al₂O₃ to metal (unlike iron).Al₂O₃ (≈ 30 %) and cryolite (Na₃AlF₆). Cryolite lowers the melting point from ~2072 °C to ~950 °C.Al³⁺ + 3 e⁻ → Al(l)2 O²⁻ → O₂(g) + 4 e⁻
O₂ + C → CO₂2 Al₂O₃(l) → 4 Al(l) + 3 O₂(g)
Worked example: How much aluminium can be produced from 100 g of alumina (Al₂O₃)?
Al₂O₃ = (2 × 27.0) + (3 × 16.0) = 102 g mol⁻¹.Al₂O₃ = 100 g ÷ 102 g mol⁻¹ ≈ 0.98 mol.Al₂O₃ give 4 mol Al → 1 mol Al₂O₃ gives 2 mol Al.Thus 100 g of alumina can yield about 53 g of aluminium (theoretical yield).
m = (Q · M) / (n · F) where Q = I t.Al₂O₃ and the endothermic melting of the cryolite bath account for the large electricity requirement.Al₂O₃ + 6 HCl → 2 AlCl₃ + 3 H₂OAl₂O₃ + 2 NaOH + 3 H₂O → 2 Na[Al(OH)₄]This links the extraction topic to the wider syllabus on oxides and their reactions.
| Metal | Main Ore | Extraction Method | Key Reaction(s) |
|---|---|---|---|
| Aluminium | Bauxite (Al₂O₃·2H₂O) |
Electrolysis (Hall–Héroult) | 2 Al₂O₃ → 4 Al + 3 O₂ |
| Iron | Hematite (Fe₂O₃) |
Reduction with carbon (blast furnace) | Fe₂O₃ + 3 C → 2 Fe + 3 CO |
| Copper | Chalcopyrite (CuFeS₂) |
Fire‑refining then electrolytic refining | Cu²⁺ + 2 e⁻ → Cu (refining step) |
Al₂O₃) is first obtained from bauxite by the Bayer process.Al³⁺ + 3 e⁻ → Al(l)2 O²⁻ → O₂(g) + 4 e⁻ (oxygen reacts with carbon to form CO₂).Al₂O₃, making electrolysis essential.Al₂O₃ is amphoteric – it reacts with both acids and bases.Create an account or Login to take a Quiz
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