| Term (syllabus) | Symbol used | Meaning |
|---|---|---|
| Experiment | – | A process that produces one result from a set of possible results. |
| Outcome (result) | – | A single possible result of an experiment. |
| Sample space | \(S\) | The set of all possible outcomes. |
| Event | \(E, F,\dots\) | A subset of the sample space; any collection of outcomes. |
| Complement of an event | \(E'\) (or \(\overline{E}\)) | All outcomes in \(S\) that are not in \(E\). |
| Mutually exclusive (disjoint) events | \(E\cap F=\varnothing\) | Events that cannot occur together. |
| Independent events | \(P(E\cap F)=P(E)P(F)\) | The occurrence of one does not affect the probability of the other. |
| Probability of an event | \(P(E)\) | Numerical measure of how likely \(E\) is to occur ( \(0\le P(E)\le1\) ). |
Probabilities can be written in four equivalent forms. All lie on the same 0 – 1 scale.
| Form | Symbol | Range | Example |
|---|---|---|---|
| Fraction | \(\dfrac{a}{b}\) | \(0\le\dfrac{a}{b}\le1\) | \(\dfrac{1}{4}\) |
| Decimal | d | \(0\le d\le1\) | 0.25 |
| Percentage | p % | \(0\% \le p\% \le 100\%\) | 25 % |
| Odds | a : b | \(a,b\ge0\) (not both zero) | 1 : 3 (equivalent to \(\dfrac{1}{4}\)) |
Used when every outcome in the sample space is equally likely.
\[ P(E)=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \]Based on actual observations. The empirical probability is the same as the relative frequency of the event.
\[ P_{\text{emp}}(E)=\frac{\text{Number of times }E\text{ occurs}}{\text{Total number of trials}} \]For a large number of trials \(n\), the expected frequency of event \(E\) is
\[ \text{Expected frequency}=n\times P(E) \]A class tosses a fair coin 40 times and records 22 heads.
Combined‑event questions are *with replacement* unless the question explicitly says “without replacement”. The following diagrammatic tools are used in the exam:
Useful for events that may overlap (e.g., “draw a red card or a face card”).
Example: From a standard deck (52 cards) find the probability of drawing a red card **or** a face card (with replacement).
Best for sequential events, especially when the question states “with replacement”.
Example: Two dice are rolled, find the probability of obtaining a total of 7.
Only 6 ordered pairs give a total of 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1).
\[ P(\text{total}=7)=\frac{6}{36}=\frac{1}{6}\approx0.167\;(16.7\%) \]Draw a grid of all possible ordered pairs. Count favourable cells and divide by total cells.
Same example as above yields a 6‑out‑36 grid, giving \(\frac{6}{36}=\frac{1}{6}\).
Only used when the question explicitly says “without replacement”. The multiplication rule becomes
\[ P(E\cap F)=P(E)\times P(F\mid E) \]Find the probability of obtaining an even number when a fair die is rolled.
Using the probability from Example 1, how many even numbers are expected in 120 rolls?
\[ \text{Expected frequency}=120\times\frac12=60\text{ even numbers.} \]A bag contains 3 red and 2 blue beads. Two beads are drawn successively without replacement. Find the probability that both are red.
\[ P(R_1)=\frac{3}{5},\qquad P(R_2\mid R_1)=\frac{2}{4}=\frac12 \] \[ P(R_1\cap R_2)=\frac{3}{5}\times\frac12=\frac{3}{10}=0.30=30\% \]Find the probability of “heads then tails”.
\[ P(H\text{ then }T)=P(H)\times P(T)=\frac12\times\frac12=\frac14=0.25=25\% \]From a standard deck, find the probability of drawing a red card **or** a face card (with replacement).
\[ P(R\cup F)=\frac{26}{52}+\frac{12}{52}-\frac{6}{52}=\frac{8}{13}\approx0.615\;(61.5\%) \]A player pays £2 to play. A fair die is rolled:
| Net gain \(x_i\) | Probability \(p_i\) | \(x_i p_i\) |
|---|---|---|
| £8 | \(\dfrac16\) | \(\dfrac{8}{6}=1.\overline{3}\) |
| ‑£2 | \(\dfrac56\) | \(-\dfrac{10}{6}=-1.\overline{6}\) |
The negative expected value means the player loses, on average, about 33 pence per play.
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